Steven H

137 reputation

	137 reputation	bio	website		visits	member for	7 months
5 badges		location			seen	Apr 22 at 18:57

16 Actions

May 16	awarded	Popular Question
Apr 22	awarded	Supporter
Apr 22	comment	Three polarizers, 45° apart Exactly what I was looking for. Thank you!
Apr 22	accepted	Three polarizers, 45° apart
Apr 22	asked	Three polarizers, 45° apart
Oct 17	asked	Adiabatic expansion
Oct 10	awarded	Student
Oct 9	accepted	Work Done by an Adiabatic Expansion
Oct 9	comment	Work Done by an Adiabatic Expansion If I use $pV = RT$, then $p = \frac{RT}{V}$. Using $\delta w = pdV$, then $w = RT \int{\frac{1}{V}} dV$. Solving this gives me $w = RT\ln(5)$, which, after plugging numbers in, gives me $w = (287)(293)\ln5 = 1.35339 * 10^5$. And I was just sent an email saying that the book's answer is wrong and this one is correct. Thank you so much for your help, I really appreciate it (and I do completely get it now)!
Oct 9	asked	Work Done by an Adiabatic Expansion
Oct 9	awarded	Scholar
Oct 9	accepted	Work Done in an Isobaric Process
Oct 9	comment	Work Done in an Isobaric Process Wait -- is it really as simple as $(RT)/P=V$ (which gives me the change since one is 0°)? It would be divided by $p$ and then again multiplied by that, so they cancel out. This actually gives what the book says is the right answer.
Oct 9	awarded	Editor
Oct 9	revised	Work Done in an Isobaric Process deleted 14 characters in body
Oct 9	asked	Work Done in an Isobaric Process