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| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 7 months |
| seen | Nov 19 '12 at 11:54 | |
| stats | profile views | 10 |
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Oct 15 |
awarded | Suffrage |
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Oct 15 |
answered | Entangled electron-positron pair |
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Oct 8 |
comment |
Extending the idea of superdense coding If you could produce $2^{n}$ orthogonal states this would allow you to signal because you would have to change the reduced density matrix of the $n-1$ qubits to obtain that many orthogonal states (since you will have as many states as it is possible to obtain on $n$ qubits) |
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Oct 8 |
comment |
Extending the idea of superdense coding @braindead $2^{n}$ states, yes; $2^{n}$ orthogonal states, no. You can see this by decomposing our bipartite state using the Schmidt decomposition $|\psi_{tot}\rangle=\Sigma\lambda_{i}|\psi_{i}\rangle|e_{i}\rangle$. Restricting ourselves to unitaries on the second party (single qubit) we can only obtain $4$ mutually orthogonal states because the only things we can change are the Schmidt basis "$e$" and the phase relationship between the two terms. |
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Oct 5 |
revised |
Extending the idea of superdense coding added 1 characters in body |
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Oct 3 |
awarded | Supporter |
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Oct 3 |
awarded | Teacher |
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Oct 3 |
awarded | Analytical |
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Oct 3 |
revised |
Extending the idea of superdense coding added 12 characters in body |
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Oct 3 |
awarded | Editor |
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Oct 3 |
answered | What is postselection? |
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Oct 3 |
answered | Extending the idea of superdense coding |
