12,141 reputation
22279
bio website
location
age 30
visits member for 3 years, 9 months
seen 3 hours ago

We once had a Nuclear Engineering proposal on Area 51, but it failed.

My academic interests are in power plants of all types, shapes, and sizes, and how well they play with each other. My hobbyist interest are kind of all over the place. I like the maker movement, I'm most interested in the sensors and data, the "internet of things" kind of stuff. In physics, I'm probably the most curious about general relativity topics, but I'm all over the place.

request sent to Physics Overflow for account creation, 7/11/2014, 1:32pm


5h
accepted Difference in vertical stratification of partial pressure due to gravity
Oct
17
comment Why heavy elements don't sink to the core?
@CuriousOne That's true, and I was walking a thin line with the comparison. The values for density should be considered "vacuum" values, constituting a minimum. While pressure increases density, the core under pressure is still less dense than Uranium metal in free space. The fact that densities combine in a non-linear fashion also obviously blows up the complexity, but I have no particular insight to share on that matter.
Oct
17
answered Why heavy elements don't sink to the core?
Oct
13
comment How to feed a small black hole against 1 TW Hawking radiation pressure?
Ugh, I kind of wish this hadn't been closed because the OP missed a major point. Whatever you feed the BH must have a wavelength smaller than the BH itself, or else it would be a 2nd law violation. Even setting aside the problem of blowing away material, you have a thermodynamic problem. If you feed it material with an accelerator, then that material would need to be below a certain entropy. This is a big theoretical problem for the scheme and needs to be answered before any other considerations.
Oct
13
comment 'Mechanical equilibrium does not necessarily mean that the pressure is same at all points of the system' - why?
The passage is perfectly clear to me, so you may need to be more verbal about what you don't understand. The pressure gradient is balancing the weight of the fluid.
Oct
11
awarded  Revival
Oct
10
comment Potential due to a continuous charge distribution on ring
@SSS Since you know the point is directly above the center of the ring, you should be able to construct a right triangle. This eliminates the need to know any angle, as reflected in the equation a^2+b^2=c^2
Oct
9
comment Potential due to a continuous charge distribution on ring
To switch between r and z I believe you're looking for the Pythagorean theorem
Oct
2
awarded  Notable Question
Sep
30
answered Why do bubble wands have ridges?
Sep
29
answered Centrifuge speed of an object higher than a stationary orbit
Sep
29
comment Do doomsday arguments influence doomsday hypotheses?
Comets have been in orbit around the sun for roughly as long as the planets. But yet, if we see a comet, we can reliably predicts its death within a million years. That's because route application of the formula ignores information we obviously have - that comets are a transitioning population from the Oort cloud to something else. Then why not say that we have similar information about humans? No one disputes that fossil fuel industry is temporary, but this says little about the future existence of intelligent life. Your "counts" are either superficial (like a Ford model number) or weak.
Sep
28
comment Potential due to a Uniform Ring
What is the question? What is the definition of $a$? Is $r$ a scalar?
Sep
25
awarded  Good Answer
Sep
23
comment Why are anti-de Sitter spaces so interesting when we believe the universe is expansionary?
I came to this exact thing reading "The Black Hole War". I kept asking myself "where is the cosmic horizon", and when we got to the part where he should have explained this, the acceleration went in the opposite direction. I might still ask something if I can obtain some novelty, but before that I might have to re-read the latter chapters again. The theorists seem to be a mess regarding how dark energy has impacted their work.
Sep
22
awarded  Nice Answer
Sep
18
accepted In black hole complementarity, does Bob literally observe Alice's death?
Sep
18
answered In black hole complementarity, does Bob literally observe Alice's death?
Sep
18
awarded  Popular Question
Sep
8
comment Steady-state adiabatic nozzle, unknown exit velocity & temperature
The diameter (and thus flow area) remains the same. Therefore, (rho V A)_1 = (rho V A)_2, which is solvable for V2 (second velocity). Now your energy equation should only have one unknown left. The m_dot in your last equation can be canceled out, but the kinetic energy term still needs V2 it looks like.