| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 8 months |
| seen | Jan 28 at 16:49 | |
| stats | profile views | 9 |
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Jan 27 |
accepted | Refraction seismology - travel time for wave |
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Jan 27 |
comment |
Refraction seismology - travel time for wave Ah! Thanks a lot. Yes, you are absolutely right. I mixed up the t-intercept and the travel time. Now it all makes sense. |
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Jan 24 |
comment |
Refraction seismology - travel time for wave Thanks. I would really, really be grateful if you could provide me with the derivation. |
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Jan 23 |
awarded | Editor |
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Jan 23 |
revised |
Refraction seismology - travel time for wave deleted 1 characters in body |
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Jan 23 |
asked | Refraction seismology - travel time for wave |
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Oct 19 |
comment |
Jumping on earth versus jumping on the moon Yes, as I wrote below, it turns out I screwed this one up by assuming $v_0$ to be equal in both jumps. Hopefully this will be the only major blunder on the exam (which I felt I did quite well on otherwise). |
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Oct 19 |
comment |
Jumping on earth versus jumping on the moon Thank you so much for your answer. I actually got a confirmation from my professor today that this was indeed how we were supposed to interpret the problem. So it turns out I was wrong after all. Too bad, but at least now I will be more careful with problems such as these in the future when it comes to making assumptions. |
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Oct 18 |
comment |
Jumping on earth versus jumping on the moon Thanks a lot! I am crossing my fingers I interpreted it correctly. The way I stated the problem is a direct copy of the way the problem was asked, and, as mentioned, this is a non-calculus based physics class. During the exam I thought perhaps our professor added the mass-information just to throw us a bit off track. Time will tell if I'm right :) |
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Oct 18 |
accepted | Jumping on earth versus jumping on the moon |
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Oct 18 |
comment |
Jumping on earth versus jumping on the moon Thanks a lot! As mentioned above, this is an introductory physics class with no calculus. So I am actually unsure as to whether or not we were suppose to assume $v_0$ is equal or not. |
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Oct 18 |
awarded | Commentator |
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Oct 18 |
comment |
Jumping on earth versus jumping on the moon Thanks a lot. This question was actually given today on a mid-term exam. However, I am taking an introductory algebraic-based physics class, so it may be quite possible that we were actually supposed to assume that $v_0$ is equal on both jumps. Is there any way to find the differences in $v_0$ without resorting to calculus? |
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Oct 18 |
asked | Jumping on earth versus jumping on the moon |
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Oct 10 |
accepted | Angular acceleration of stone disk |
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Oct 10 |
comment |
Angular acceleration of stone disk Thank you very much! I really appreciate your input! |
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Oct 9 |
comment |
Angular acceleration of stone disk @David Zaslavsky: The answer above was to a comment from someone else (the comment is deleted now I see). So I still don't understand why my second approach above gives the incorrect answer. |
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Oct 9 |
comment |
Angular acceleration of stone disk Well, I interpreted the problem such that $F$ is the actual frictional force. After all, I used this value to calculate the torque, and then my answer became correct. |
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Oct 9 |
asked | Angular acceleration of stone disk |
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Oct 5 |
accepted | Torque and equilibrium |