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Aug
25
comment Net torque on a frictionless pulley
Well,the hint you are giving is already mentioned by me in the previous post.The friction will not cancel out.Anyways,thanks for the help .
Aug
25
comment Net torque on a frictionless pulley
Nice! In the same fashion can you explain how is the downward force on the pulley T1+T2 ? If I consider pulley with the string then I am convinced that the net downward force on the pulley is T1+T2 but what if we see pulley in isolation .The tangential force on the pulley is by friction and the normal force from the string acts radially .How is their net resultant in vertical direction equal to T1+T2 ? I hope I am clear with my question :)
Aug
25
comment Net torque on a frictionless pulley
Iα = (T2-T1)R - fr Where T1 and T2 are the tensions, R is the pulley radius, r is the axle radius and f is the frictional force at the axle.
Aug
24
comment Net torque on a frictionless pulley
I am pretty surprised that my question has been downvoted.I am curious to know who has given it a negative vote.Is there a way to know which member has downvoted or upvoted you ?
Aug
24
awarded  Commentator
Aug
24
comment Net torque on a frictionless pulley
The torque equation you have written is incorrect.My simple question is how does torque due to friction between string and pulley resulting in a value (T2-T1)R ?It is the friction which causes a torque on the pulley ,not tensions .I hope I have made myself more clear.
Aug
23
revised Net torque on a frictionless pulley
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23
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Aug
23
revised Net torque on a frictionless pulley
added 15 characters in body
Aug
23
reviewed Reject suggested edit on Net torque on a frictionless pulley
Aug
23
comment Net torque on a frictionless pulley
A frictionless pulley means friction is absent between the pulley and the axle(bearings).There is sufficient friction present between the pulley and the string such that no slipping occurs.
Aug
23
revised Net torque on a frictionless pulley
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Aug
23
asked Net torque on a frictionless pulley
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May
18
comment Force Between Two Conducting Spheres
@joshphysics "This will cause the charges on opposite spheres to be further away from each other, and the force of repulsion to be less than in the case of a uniform surface charge distribution" Why would the force of repulsion be less ? It seems intuitive but what is the reason ? Yes,the distance increases ,but we simply cannot apply the inverse square law of coulombs force ,since they are not point charges .
May
16
comment Rod slipping against block due to gravity?
All surfaces are smooth
Jan
17
comment What is the role of battery across a Parallel plate capacitor having equal charge?
How can we say that the electric field outside the plate is same as before the battery was connected? If we could only prove this then the constant charge density on the outside surface will hold good .Isnt it ??