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I design chips, semiconductor devices, Semiconductor processes and analog IC's.


Apr
29
answered How can Ohm's law be correct if superconductors have 0 resistivity
Jan
8
answered Current through the reverse biased junction in transistor
Jan
8
answered Schematic design of the apparatus (photoelectric effect)
Oct
2
answered What forces are at play when molecules wiggle (due to heat)?
Sep
27
answered What's driving the bucket up?
Sep
26
answered How to make something charged using electricity?
Sep
22
comment Misaligned Mirror on Michelson Inferometer
Oops! Sorry the above comment should read "doesn't" NOT "does". Fat fingers.
Sep
21
comment Misaligned Mirror on Michelson Inferometer
I'll give you a hint. It does matter which mirror is misaligned.
Sep
20
answered Misaligned Mirror on Michelson Inferometer
Sep
14
answered Why there is electromagnetic resistivity in vacuum?
Sep
13
comment Is emission/absorption of a photon lossy?
Or if the material is rough (think of powdered glass) then the photon energy will go purely into heat.
Sep
12
comment Is emission/absorption of a photon lossy?
Think about what you mean by "incapable of absorbing". That means the 'target" is transparent to that wavelength. In an ideal world the answer is no, in real life imperfections will lead to some loss. And if there is an index of refraction change (almost certainly is) then a certain number of photons will be reflected and a certain amount transmitted at the boundary.-> fresnel eqn's.
Sep
5
awarded  Teacher
Sep
5
answered Mass vs. weight on a spring-loaded bathroom scale
Sep
1
comment Is emission/absorption of a photon lossy?
It is not at all misleading. There is always conservation of energy. If you apply that uniformity the answer is always NO - there is never any loss. So why ask the question? I assumed the person didn't want an tautological answer and that had some fundamental understanding and was asking amore interesting question. So I'll be more explicit and rephrase the question as " is Absorption and re-emission lossy or not". Keep in mind that if you have emission then there must be an electron involved - reflection is something different (even though it does involve electrons).
Aug
31
answered Is emission/absorption of a photon lossy?