# Alec S

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bio website location University of California Los Angeles, CA age member for 1 year, 3 months seen Nov 20 at 17:24 profile views 169

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 Nov24 awarded Popular Question Nov11 awarded Notable Question Oct31 awarded Popular Question Oct31 comment Quantum Entanglement - What's the big deal? @joshphysics No biggie. Oct31 comment Quantum Entanglement - What's the big deal? @joshphysics So Josh.. I'm going to nitpick a little... The paradoxical thing, at least to me, is that when you measure an electron in NY, the other electron in LA will always be flipped the other way, even if you measure it before enough time has passed for the "information" to reach it. It's not just like marbles where nobody knows which marble is which. It's like you have two marbles, each flickering black and white, and when you measure one to be black, the other, while still flickering, will always turn out to be white -- even if you measure it "instantly" afterwards. Oct26 comment Intuitively, how can the work done on an object be equal to zero? There's no reason to make the font this big. Oct18 accepted A “Hermitian” operator with imaginary eigenvalues Oct18 comment A “Hermitian” operator with imaginary eigenvalues @EmilioPisanty furthermore, what is the erroneous step in the following calculation? $\langle\psi_{\lambda}(x)|{\bf H}\psi_{\lambda}(x)\rangle= \langle{\bf H}^{\dagger}\psi_{\lambda}(x)|\psi_{\lambda}(x)\rangle=\langle{\bf H}\psi_{\lambda}(x)|\psi_{\lambda}(x)\rangle=\langle\psi_{\lambda}(x)|{\bf H}\psi_{\lambda}(x)\rangle^{*}.$ All inner products are presumably evaluated in the same Hilbert space. Oct18 comment A “Hermitian” operator with imaginary eigenvalues @EmilioPisanty, interesting answer, especially the second paper. I was wondering if you could explain exactly how the domains $D({\bf H})$ and $D({\bf H^{\dagger}})$ differ. After all, it seems (prima facie) $D({\bf H})=D({\bf T})\cap D({\bf T^{\dagger}})=D({\bf H^{\dagger}})$. Oct17 revised A “Hermitian” operator with imaginary eigenvalues added 1 characters in body Oct17 awarded Nice Question Oct17 comment A “Hermitian” operator with imaginary eigenvalues @BMS Like, you want me to type it out? It's a quick calculation. You just have to be careful when calculating $d/dx |x|^{-3/2} = (-3/2){\rm sgn}(x)|x|^{-5/2}$. Oct17 revised A “Hermitian” operator with imaginary eigenvalues added 21 characters in body Oct17 awarded Citizen Patrol Oct17 asked A “Hermitian” operator with imaginary eigenvalues Oct16 comment Harmonic Oscillator (Quantum Mechanics) For the second part: compute $[H,a_{+}]$. What do you get? Apply this commutator to the wavefunction. Sep26 answered Distribution of point charges on a line of finite length Sep25 answered Angular momentum of quantum system Sep25 awarded Popular Question Sep24 comment Electrostatics:2 concentric spheres What is the question? How is what possible?