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I enjoy studying physics as a hobby and think physics stack exchange is great!

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combined Stack Exchange profile for Hal Swyers


Sep
28
revised Show that the Hamiltonian operator commutes with the angular momentum operator
edited tags
Sep
28
asked Eternal clocks and 4D spacetime crystals
Sep
28
asked Physics of homebrewing heat exchangers
Sep
28
revised Why is the lightness of particles remarkable?
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Sep
28
answered Why is the lightness of particles remarkable?
Sep
27
answered Energy is quantized
Sep
27
revised How did Einstein derive general relativity?
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Sep
27
comment What is a good non-technical introduction to theories of everything?
@Dilaton Probably true, I am just to the point where I think people need to be realistic in the level of effort they are going to have to invest in order to get a good understanding to discuss TOE's. Most popular discussions really barely touch on some of the more difficult concepts. Algebra is really not too difficult, its just that we don't introduce it early enough in the curriculum for people to make the mental connections.
Sep
27
revised What is a good non-technical introduction to theories of everything?
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Sep
27
answered Tried to do the double slit experiment, failed. Why?
Sep
27
answered What is a good non-technical introduction to theories of everything?
Sep
27
answered How did Einstein derive general relativity?
Sep
27
comment The radius of the universe and time
cont. As far as expanding into a space, this is not the conception that astronomers and cosmologists like. First, expansion implies a time derivative, which if you equate our notion of time into a spatial dimension for expansion, you would still need another variable of time, which is unphysical. GR assume a 4-d spacetime manifold, and the expansion parameter is the cosmological constant $\Lambda$ in the equation, $R_{ij} - \dfrac{1}{2} Rg_{ij} + \Lambda g_{ij} = \kappa T_{ij}$
Sep
27
comment The radius of the universe and time
@GaryBeilby From a metric perspective, there is a relationship between space and time. $ds^2 = dx^2 + dy^2 + dz^2 - c^2 dt^2$, where space is flat when $ds^2 = 0$. In that case we can write $c^2 dt^2 = dx^2 + dy^2 + dz^2$, which if we equate $dr^2 = dx^2 + dy^2 + dz^2$ we can write $c^2 dt^2 = dr^2$ and then $c^2 = \dfrac{dr^2}{dt^2}$, which shows that time and space share an inverse relationship. As such they are conjugate diameters of a hyperbola. In this sense there is a proper time that can be equated to a proper distance. to be cont.
Sep
26
awarded  Scholar
Sep
26
comment How is the singularity in Newtonian gravity resolved?
Good points, and I will accept the answer, however Newton was smart enough to build the relationship between kinetic and potential energies and equate potential energy to gravitational force. So even if he didn't have a clear equivalence of mass to energy, he certainly had enough knowledge to parametrically manipulate the relationships. I just suspect that he was aware of some of these issues and was actually investigating them.
Sep
26
accepted How is the singularity in Newtonian gravity resolved?
Sep
26
comment How is the singularity in Newtonian gravity resolved?
Thanks, I would accept that except if Newtonian gravity admits infinite velocities, then it has to allow for infinite kinetic energy for an object, which would mean it has infinite energy density.
Sep
26
asked How is the singularity in Newtonian gravity resolved?
Sep
25
revised How the bond angle of a water molecule is measured?
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