| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 2 years, 4 months |
| seen | 23 mins ago | |
| stats | profile views | 15 |
|
Apr 5 |
awarded | Enthusiast |
|
Nov 22 |
awarded | Scholar |
|
Nov 22 |
accepted | A step in the derivation of the magnetic momentum of the electron in Zee's QFT book |
|
Nov 22 |
comment |
A step in the derivation of the magnetic momentum of the electron in Zee's QFT book This is basically identical to the answer by A friendly helper and both are correct. I am accepting his answer because he was slightly quicker but many thanks anyway. |
|
Nov 22 |
comment |
A step in the derivation of the magnetic momentum of the electron in Zee's QFT book Right. I guess I was blinded by the appearance of $\partial_\mu A_\nu - \partial_\nu A_\mu$ so I forgot that the $\partial$s were still operating on everything to their right. Thanks. |
|
Nov 22 |
asked | A step in the derivation of the magnetic momentum of the electron in Zee's QFT book |
|
Aug 23 |
awarded | Citizen Patrol |
|
Mar 12 |
awarded | Supporter |
|
Mar 9 |
awarded | Student |
|
Mar 9 |
comment |
Why are Saturn's rings so thin? In inelastic collisions between the ring particles angular momentum is preserved but kinetic energy is lost. So the final rotation axis of the rings is given by their initial angular momentum but it is the dynamical evolution of the rings that makes them flat and thin. |
|
Mar 9 |
awarded | Teacher |
|
Mar 9 |
answered | Why are Saturn's rings so thin? |
|
Mar 9 |
asked | Did Rutherford invent the smoke detector? |