Lucy Brennan
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Comment everywhere
 Nov 1 awarded Popular Question Aug 8 revised Voltage and resistance in series connection Changed U to V Aug 8 revised Voltage and resistance in series connection Changed U to V Aug 8 answered Voltage and resistance in series connection Aug 7 comment Voltage and resistance in series connection I know the definition as energy per charge. Aug 7 asked Voltage and resistance in series connection Jul 29 awarded Supporter Jul 29 accepted Radioactive decay, why such unintuitive formula? Jul 29 accepted How is a cathode ray tube different from beta minus radiation? Jul 29 comment How is a cathode ray tube different from beta minus radiation? Great answer, thank you very much :) Jul 28 comment How is a cathode ray tube different from beta minus radiation? What is the maximum energy that an electron can carry when being the result of Beta decay? Jul 28 comment How is a cathode ray tube different from beta minus radiation? FYI: Electron beams are being used for radiation therapy, but I don't know to what extent. See Electron therapy or the famous Therac 25 that killed a few people because of faulty programming. Jul 28 awarded Scholar Jul 28 comment Radioactive decay, why such unintuitive formula? I'm afraid that I don't understand it, and I guess I just don't have the prerequisites to. But thanks in any case :) Jul 28 asked How is a cathode ray tube different from beta minus radiation? Jul 28 comment Radioactive decay, why such unintuitive formula? I think you misunderstood me, because I already understand what you tell me in your comment. I restate my point: If $N_0 = 10$, $\lambda = 0.1$ and $\Delta t=1$, then you get 9.048. Whereas $(1- \Delta t \Lambda) = 0.9$. Those two numbers are simply not the same. With higher values of $\Delta t$ the difference is greater. Jul 28 comment Radioactive decay, why such unintuitive formula? hat is only true for sufficiently small $\Delta t$. I understand the concept of exponential growth, as in the bank. But in fact the bank uses the formula that I prefer Jul 28 awarded Student Jul 28 comment Radioactive decay, why such unintuitive formula? Thanks, but I do understand the derivation. I just don't see why the former formula is preferred in textbooks when the latter to me (and my co-students) seem much more intuitive. In fact even my teacher accidentally said that after one time unit a fraction of $\lambda$ will have decayed, which is only true if the time unit is defined to be sufficiently small. Jul 28 comment Radioactive decay, why such unintuitive formula? Yes, k will depend on the size of the time unit used. But so does $\lambda$, since $\lambda = -ln(1-k)$. Right?