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visits member for 2 years, 10 months
seen Mar 19 at 1:11

I'm a phd student in University of Toronto (math department), my interests are: commutative algebra, homological algebra and algebraic geometry.


Mar
8
accepted Decomposition of the gravitino into helicity $\pm \frac{3}{2}$ and $\pm \frac{1}{2}$ components
Mar
8
comment Decomposition of the gravitino into helicity $\pm \frac{3}{2}$ and $\pm \frac{1}{2}$ components
Do you mean something of the type $\partial_{-} \psi_{+}=\partial_{+} \psi_{-}=0$ in light-cone world sheet coordinates?
Mar
8
comment Decomposition of the gravitino into helicity $\pm \frac{3}{2}$ and $\pm \frac{1}{2}$ components
I understand everything, except your remark on helicity operator. For me helicity is the projection of "projection of spin in the direction of momentum". That is the part I don't understand: how all this is related to momentum? What you calling helicity for me looks like chirality.
Mar
7
asked Decomposition of the gravitino into helicity $\pm \frac{3}{2}$ and $\pm \frac{1}{2}$ components
Jan
24
revised Are end points of an open bosonic strings orthogonal to D-branes?
edited title
Jan
24
comment Are end points of an open bosonic strings orthogonal to D-branes?
Yes, I agree with this, but if we don't look at momentum and just look only on coordinates, is not it also true that Neumann's BC's in tangential directions imply orthogonality as I claim?
Jan
24
comment Are end points of an open bosonic strings orthogonal to D-branes?
You saying that there are no Dirichlet conditions in tangental directions, that is just part of the definition. But I'm asking: what second part of the definition (Neumann b.c. in tangential directions) imply?
Jan
24
asked Are end points of an open bosonic strings orthogonal to D-branes?
Sep
24
awarded  Autobiographer
Sep
20
awarded  Curious
Sep
19
asked Left (right) invariant vector fields on superspace
Apr
10
awarded  Yearling
Apr
9
asked Anti-symmetric forms on Dirac spinors
Mar
30
awarded  Scholar
Mar
30
accepted The BRST construction for YM with or without auxiliary field
Mar
29
asked The BRST construction for YM with or without auxiliary field
Nov
7
comment Dirac equation as Hamiltonian system
Yes, this is constrained system. I'm trying to extend phase space to super space and get super Poisson bracket that would give a meaningful answer. By the way, everything you wrote is classical field theory, because your spinors are fields on space-time not operators (I look at the situation from QFT point of view, not QM).
Nov
7
comment Dirac equation as Hamiltonian system
Why you ignore field $\bar{\Psi}$ in the bracket?
Nov
6
comment Dirac equation as Hamiltonian system
@juanrga I mean Hamiltonian formalism for fields: if you have Lagrangian density you can ask what is Hamiltonian density and could you rewrite Euler-Lagrange equations as Hamiltonian equations with respect to some bracket on functionals on fields.
Nov
6
awarded  Editor