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seen Oct 1 '13 at 18:56

Feb
1
awarded  Popular Question
Sep
29
awarded  Notable Question
Aug
29
comment Frequency of small oscillation of particle under gravity constrained to move in curve $y=ax^4$
thanks @MichaelBrown fixed it :)
Aug
29
revised Frequency of small oscillation of particle under gravity constrained to move in curve $y=ax^4$
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Aug
28
revised Frequency of small oscillation of particle under gravity constrained to move in curve $y=ax^4$
added 1022 characters in body
Aug
27
awarded  Yearling
Aug
27
comment Frequency of small oscillation of particle under gravity constrained to move in curve $y=ax^4$
@Spaderdabomb I am using Lagrangian
Aug
27
comment Frequency of small oscillation of particle under gravity constrained to move in curve $y=ax^4$
@joshphysics can't I express $V$ as function of $x$ since height is linear function of height and height is the quartic function of $x$?
Aug
27
revised Frequency of small oscillation of particle under gravity constrained to move in curve $y=ax^4$
edited title
Aug
27
asked Frequency of small oscillation of particle under gravity constrained to move in curve $y=ax^4$
Aug
22
accepted what molecule would have molar entropy $R \ln 2$ at $0K$?
Aug
22
asked what molecule would have molar entropy $R \ln 2$ at $0K$?
Aug
22
comment volume of phase space of composite microcanonical ensemble
thanks, i get your point, i was being foolish. to put simply, each particle is assigned $(p,q)$, and the volume of phase space is a hyperspace formed by each independent coordinates for each particle. thanks (y)
Aug
22
accepted volume of phase space of composite microcanonical ensemble
Aug
22
asked volume of phase space of composite microcanonical ensemble
Aug
9
revised Transformation of $t=0$ line in moving frame of reference
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Aug
9
comment Transformation of $t=0$ line in moving frame of reference
@dmckee i was just wondering how it has been assumed on this page just for rotation of axes. The first equation is $x=vt$ which is the speed of ref. frame moving at constant speed and this line would represent new $x' = 0$ i.e. future of coordinates. I was just wondering how the second transformation of axes $t=0$ is rotated.
Aug
9
comment Transformation of $t=0$ line in moving frame of reference
the other transformation $x=0$ transforms into $x - vt = 0$ without Lorentz transformation.
Aug
9
comment Transformation of $t=0$ line in moving frame of reference
@Dimension10 can't this be done without Lorentz transformations?
Aug
9
revised Transformation of $t=0$ line in moving frame of reference
added 6 characters in body