# Tag Info

## New answers tagged wavelength

4

You have $\lambda=d\frac x{\sqrt{x^2+z^2}}$ It looks OK to me. The errors in each $x,z$ are about one part in $1000$ and your final error is about that. Since the derivatives are a bit less than $1$, that seems sensible.

1

The Balmer series is the light emitted when the electron moves from shell $n$ to shell 2. So the lowest energy line is emitted in the transition from $n = 3$ to $n = 2$, the next line is from $n = 4$ to $n = 2$, and so on. But the energy does not keep going up as you increase the value of $n$, because the energies of the orbitals (wrt the vaccum) tend to ...

0

One common way that this happens is through spontaneous parametric down-conversion. From Wiki: an important process in quantum optics, used especially as a source of entangled photon pairs, and of single photons. A nonlinear crystal is used to split photons into pairs of photons that, in accordance with the law of conservation of energy, have combined ...

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If $\Delta \lambda$ is much smaller compared to either $\lambda_1$ or $\lambda_2$(it doesn't really matter, it should be much smaller than both), then we can make the following approximation: $$|\Delta E|= \left|\Delta \left( \frac {hc}{\lambda}\right)\right|\approx\left|\frac {hc\Delta\lambda}{\lambda^2}\right|$$

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It is absolutely correct that in vacuum all colors of light travel with same speed and this is why a white ray travels through the vacuum without suffering any dispersion...

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