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The simple answer, which is what I think you're hoping for is the following: At constant volume, the system (by definition) is not able to do work on the surroundings because work involves a change in volume. All the heat you put in is spent raising the temperature (internal energy). At constant pressure, some of the energy you put in goes into raising the ...


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First law of thermodynamics $$\delta Q=\delta E+p\delta V $$ $$\therefore\frac {\delta Q}{\delta T} = \frac{\delta E}{\delta T}+nR$$ As $p\delta V$ can be written as $nR\delta T$ When volume is constant $$\delta Q= \delta E $$ $$\therefore\frac {\delta Q}{\delta T} = \frac{\delta E}{\delta T} $$ $\frac {\delta Q}{n\delta T}$ is Molar heat capacity. ...


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Hint : In the Figure below what is the height of your infinitesimal cylinder ??? (a) The red one ($d\mathbf{h}$) ??? (b) The blue one ($d\mathbf{s}$) ???


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The boiling water will boil at a constant temperature. As long as the can is in the boiling water, you will not need to worry about the temperature of the stove. If this experiment is run at sea level, and you are using pure water, the can will remain at 100 deg C throughout the experiment. If you are at an elevation higher than sea level, and you want to ...


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The idea gas law work; more specifically Boyle's law is a reciprocal law. Pressure and volume are inversely related. When you increase volume by a factor of 1.0666 (by 6.66%), you decrease pressure by $\frac{1}{1.0666}$. Pressure is inversely proportional to volume. $P \propto \frac{1}{V}$ So when you increase pressure by a certain factor, volume ...


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The question comes down to buoyancy: is the mass of the flatus inside the body divided by its volume less than or greater than the mass of an equal volume of atmospheric air? To answer this we need to look at the density of atmospheric air, as well as the density of flatus. Let's start with the atmosphere. We usually see the density of air quoted as 1.2 ...



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