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In a perfect lattice, the resistance would be zero. The reason for resistance is electrons being scattered by departures from a perfect lattice, for example lattice vibrations or imperfections in the lattice due to, for example, the presence of impurities or irregularities.


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Metals are in solid state. So conductors are basically solids. (Don't take it too much. There are no solids in quantum physics). A conductor is hence characterized by tightly packed atoms with plenty of availability of valence electrons that are ready to get off from what that holds them. Also a good conductor like silver, iron etc. have very good atomic ...


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Your wording is a little off. SMH doesn't care about the size of displacement. SHM is the lowest order approximation to a general oscillation. A general oscillation does care about the size of the displacement, and when you ignore the higher order effects you will miss various phenomena. Examples of things you will not be able to describe are harmonic ...


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When you ignore higher orders in the force, assuming it is linear in the position, you are assuming the potential energy is quadratic at most (quadratic, parabolic or harmonic approximation). Then you loose global information about the potential. We are not able to say for example whether the movement of the particle is bounded or unbounded as we increase ...


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A single mass attached to a spring has only one degree of freedom. Here you have a diatomic molecule, which in a physical point of view can be visualized as two masses connected by a spring. A single particle has three degrees of freedom. When you attach another particle, that is a constraint, which reduces the overall degree of freedom to two. Now, about ...


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The answer by Tom is correct. I would like to add a few more points about scattering phenomena. Using Raman spectroscopy rotation and vibration of these homo-nuclear molecules are easily probed. (Classically, scattering is explained by induced dipole moment; while Quantum-mechanical treatment is based on the Perturbation theory). However, Raman signal is ...



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