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The word "horn" conveys directionality, i.e. a specific direction in which the energy is transferred. It would be amazing if there were no currents in the liquid considering also reflections from the beaker wall. In this paper the momentum of a sound wave is calculated. Looking up ultrasonic baths I found this video which shows that there too the ...


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It's impossible to say without seeing your experimental setup, but an obvious explanation is that the ultrasound is heating the water and you're seeing plain old thermal convection currents. You say you don't get convection currents in an ultrasonic bath, but my recollection of using (admittedly quite powerful) ultrasonic baths is that you get quite ...


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Taste: There are 5 basic tastes that the human tongue can detect. They are sweet, savory, salty, sour and bitter. These are detected by taste receptor cells on our tongue, I won't go deep into the biology part. The basic tastes of sweet, salty and sour have different thresholds, or concentration levels, at which they can be detected. In other words, it is ...


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Taste and smell are mediated by receptors in your body that molecules can attach to. These receptors then give off an electrical signal which is translated in the brain to a certain taste or smell. The details of this are biological and not of importance here. So no, there is no relevant frequency or even wave-like behavior. Touch is a very different thing. ...


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I think it has more to do with surface tension. Added: When an object is floating on the surface of water, it bends the surface to support it. This bending extends outward from the object decreasing with distance (much like gravity). When 2 objects are near each other, they feel the bent surface and move down the slope (they attract each other).


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Say the density of the string is $\mu$ and the tension is $T$. It's clear that the kinetic energy of an infinitesimal piece of string is $$dT = \frac{1}{2} (\mu \, dx) u_t(x)^2$$ The length of the infinitesimal piece of string from $(x, u(x))$ to $(x + dx, u(x + dx))$ is \begin{align} d\ell &= \sqrt{dx^2 + (u(x+dx) - u(x))^2} \\ &= \sqrt{dx^2 + ...



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