# Tag Info

## New answers tagged turbulence

4

The key is the Reynolds number, $$Re=\frac{\rho LV}{\mu}=\frac{LV}{\nu}\tag{1}$$ where $L$ and $V$ are characteristic lengths and velocities of the particular problem and $\mu$ & $\nu$ are the dynamic & kinematic viscosities, respectively. If you multiply (1) by $\rho LV/\rho LV$, you get $$Re=\frac{\rho L^2V^2}{\mu LV}$$ The numerator is the ...

Top 50 recent answers are included