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I don't see how the existence of insulanium violates any of the laws of thermodynamics : The 1st Law is a statement that energy is conserved. But there is no suggestion that energy is being created or destroyed here. The 2nd Law states that the entropy of an isolated system only increases, never decreases. This is not saying that the entropy cannot stay ...


Influence of Magnetic Domain Walls and Magnetic Field on the Thermal Conductivity of Magnetic Nanowires H.T. Huang et al., “Influence of magnetic domain walls and magnetic field on the thermal conductivity of magnetic nanowires,” Nano Letters, vol. 15, pp. 2773-2779, 2015.


Real world assumptions: No temperature gradients over the cross-section of the pipe. Plug flow (turbulent flow). Water heat capacity $c_p$ and density $\rho$ are temperature invariant. Consider an infinitesimal mass element $dm$ at temperature $T(x)$ travelling down the pipe at speed $v$. We apply Newton's law of cooling to it: $$\frac{dQ}{dt}=hdA\big(...


No, it is not possible. Any material has black body emission which is a distribution of wavelengths across the electromagnetic spectrum. All materials have specific absorption frequencies at which they will absorb a photon. This will result in a transfer of energy from the hotter material to the colder one.


No, any material with a finite temperature will release thermal radiation, including mirrors, and it's not possible to make a mirror that's perfectly reflective. Generally speaking, the best you can do is limit an object to only radiative heat exchange (i.e. no conductive or convective heating) which is why nice thermoses are vacuum-insulated.


According to the three laws of thermodynamics, insulanium cannot make a drink hot or cold forever. I guarantee you will feel the heat and that it will look almost like a mirror at almost all frequencies. James Clerk Maxwell, the eminent Scottish physicist, came up with something called Maxwell's Demon (still being studied) that may debunk the second ...


I dont think it is possible to make anything 100% reflective although we can get arbitrarily close. The reason may be explained by tunneling by photons. Also,the entropy of an isolated piece of insulanium must increase with time. I think you can see now why such a thing is very very unlikely.


The 'go to' partial differential equation here is surely the Heat equation (Fourier), here in one dimension: $$\frac{\partial T}{\partial t}=\kappa \frac{\partial^2T}{\partial x^2}+\frac{\dot{Q}(x,t)}{c_p\rho }$$ It can be easily expanded into three dimensions or expressed in polar, spherical or cylindrical coordinates. It's not clear from your question ...


You are mistaken. You seem to be assuming that there is some kind of inertia in the process of heat transfer, as in water sloshing about in a tank. There is no such inertia here, so there is no oscillation. You write: Since heat has been transferred from A to B, unless I'm mistaken this will place B momentarily at a higher temperature than A. Yes, you ...


If you are using only the "superheat" in the steam, and letting it leave the coffee before it condenses, you are using specific heat only. This means that you will not be diluting the coffee, but it will take a relatively large volume of steam to do the job because the specific heat of the steam will be somewhat lower for a given mass of steam than the ...

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