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New answers tagged thermal-conductivity

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Not quite - you want the cold sink to be as cold as possible. The cold sink is the cold air (or water or coolant) flowing over the heatsink. The heatsink is designed to efficiently connect the chip to the cold sink, so it needs to be as low resistance as possible. In thermodynamic calculations consider the chip==heatsink and the airflow to be the cold ...

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The fact that it is a cylinder has to be taken into account. Usually $\frac{dQ}{dt} = \lambda \frac{A}{d}\Delta T$, where A is the surface perpendicular to the heat flow and d is the thickness of the material between the to temperatures. As the temperatures are being maintained, the heatflow is a constant, but being a cylinder the outer surface is larger ...

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