New answers tagged superalgebra
It is true that physicists often talk about $X$ being nilpotent when they really mean that $X$ squares to zero $$X^2~=~0,$$ in particular in the topics with Grassmann-odd symmetries, such as, e.g., Poincare supersymmetry or BRST symmetry. But not in Ref.1. By $X$ being nilpotent is here meant the standard mathematical definition of being nilpotent: ...
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