# Tag Info

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Does the fact that protons and neutrons have larger mass than electrons mean they're bigger in size? No. The electron and muon are both believed to be "point-like" (which really means smaller than we can measure" despite having $\frac{m_\mu}{m_e} \approx 200$. That is not to say the proton isn't bigger---it is---but that mass does not imply size in any ...

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To begin with electrons are not composite. It is baryons and hadronic resonances that are composites of quarks. Hadrons are held together by the strong forces between quarks. These forces, in contrast to the electromagnetic ones which fall with distance as 1/r^2 (and thus allow us to detect free electrons, whose potential falls like 1/r), they behave ...

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You apply a (net) force (i.e. push it). Recall that the generalized version of Newton's 1st law is that force is proportional to the rate of change in momentum: $$\vec{F} = \frac{\mathrm{d} \vec{p}}{\mathrm{d}t} \,,$$ or in the language of impulse ($J$) $$\vec{J} = \Delta\vec{p} = \langle \vec{F} \rangle \Delta t \,,$$ with $\langle \rangle$ meaning ...

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How is it possible to see/detect a probability density wave ? It isn't possible. The image is a visualization of an interference pattern from which the nodal structure of the orbital can be inferred. From a Physics World article: In the new work, Aneta Stodolna, of the FOM Institute for Atomic and Molecular Physics in the Netherlands, along with ...

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I can't give a complete answer because it seems there is still some research ongoing. Unlike what most people have been taught, water is not colorless. At least, large masses of water will be seen blue, such as the sea or a swimming pool. (Left: tube if filled with (light) water. Right: empty tube.) The fact is that water absorbs mostly the red ...

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The pion does indeed annihilate into photon pairs. But it is an EW process, so the lifetime is large and the pion is long lived. Actually, setting EW couplings to zero the pion would be stable since there would be no lighter hadron it could decay into.

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Perhaps I do not understand the question. When, for instance, a photon is observed in a state of circular polarization it is simultaneously in a superposition of linear polarization states. Every pure quantum state $\psi$ is always a coherent superposition of other quantum states eigenstates of observables which are not defined in the state $\psi$. A ...

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A nanoscope in the sense you're talking about would be physically impossible, because things which are smaller than the wavelength of light don't reflect light. They do scatter light, but that's a different process which doesn't form a coherent image. Visible light has wavelengths between about 400 and 700 nanometers, so anything smaller than that - ...

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The title of this question refers to the emission of light from an incandescent light bulb, and then the body of the question asks for Planck-scale details of the physics happening there. Well, that would be a lot of work to answer. Suppose it's a tungsten filament. Then there's a molecular lattice of tungsten atoms, i.e. a lattice of nuclei surrounded by ...

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In contrast with the previous incorrect answers that I hadn't noticed, there isn't any ambiguity or confusion about the Bose-Einstein or Fermi-Dirac statistics for composite systems such as atoms. A particle – elementary or composite particles – that contains an even number of elementary (or other) fermions is a boson; if it contains an odd number, it is a ...

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The proton and electron exchange information via a gauge boson, in this case, a virtual photon. This is how the electromagnetic interaction is mediated. As for your other question, the electron will get decelerated and deflected and emit a photon, releasing some of its energy in a process called Bremsstrahlung

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I think you are correct in being confused. The earth's magnetic field, or any external to the atom magnetic field , can distort orbitals but is not the creators of them. Orbitals are the locus in space where the probability of finding an electron is large enough to be measurable. In the quantum mechanical framework orbitals play the role orbits have in ...

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To start answering this question let us talk about a diatomic molecule. In that case we can define the internuclear axis as the z axis in the molecular frame, and talk about the orientation of the various atomic orbitals with respect to that. There is a natural choice of orientation along the bond. For an isolated atom there is no preferred z axis to ...

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The term "element" is reserved for atoms that have a nucleus that is a combinations of at least one proton and optionally one or more neutrons. Also, only a difference in the number of protons makes a nucleus considered that of a different element. Changing just the number of neutrons only makes a different isotope. Changing the number of electrons is ...

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But im struggling to understand where exactly the potential energy is stored in mass. It is largely in the binding energy of the protons and neutrons in the matter. This represents the vast majority of the rest mass of the nucleons. However, the fundamental particles also have a non-negligible rest mass themselves. This is true for the quarks that ...

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On the electron 'cloud' pictures: what is usually shown is a surface where the probability (per unit volume) of finding an electron (the magnitude of the wave function squared) is constant. 'Inside' the volume, the probability (per unit volume) is higher in this case, so indeed these shapes show the volume where the probability of finding an electron is ...

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Orbitals (s, p, ...) are special wave functions $\psi$ that are used to approximately describe one electron in spherically symmetric potential due to nucleus (and for many-electron atoms, also due to other electrons). $\psi$ is a mathematical function that is useful in the process of finding some interesting numbers, like expected average electric moment of ...

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As far as resolution goes, right now the best in practice are high resolution transmission electron microscopy (which involves firing high energy electrons), high resolution scanning force microscopy (which involves a very sharp tip vibrating above a surface), and the classic scanning tunneling microscopy (which involves conduction through a very narrow ...

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it is not just that every transition would result in the change of spin this occurs only some times which is explained below Electron Spin The Pauli Exclusion principle states that two electrons in an atom cannot have the same four quantum numbers (n, l, ml, ms) and only two electrons can occupy each orbital where they must have opposite spin states. These ...

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You're misinterpreting the separation energy $S_\mathrm n$. If you wanted to start with $^{236}$U and end up with $^{235}$U and a neutron at rest, you'd have to add 6 MeV. When the neutron is captured, it's into some nucleon orbital 6 MeV above the $^{236}$U ground state; as the excited nucleus cools that energy gets distributed among all the nucleons. ...

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C: See "Quantum Mechanics". More specifically you're wanting solutions to the Schrodinger Equations that represent your system. In this case that is an electron represented by a probability density function $$\psi (\vec{x},t )$$ under a potential $$V(\vec{x})$$ which is the potential energy function of the system. This contains information regarding the ...

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If one uses the sphere volume as $\pi^{n/2}/\frac n2 !$ and then apply stirling's approximation to $n! = (n/e)^n$, then one gets $(2.\pi.e/n)^{n/2}$ as the approximation for the volume of an n-sphere. This then equates to a cube of edge $\sqrt{2\pi e/n}$. Of course, one can use by way of limits, that even a cube of side $1/2$ must 'go to zero', even ...

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For example, how many quarks are in my brain(easy to find out once you know how many atoms there are)? Actually it's easier to count how many atoms are in your brain than how many quarks are in your brain. As you may know there are three quarks per nucleon in your brain... but this is not the whole truth. The force the binds quarks together creates a ...

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Specific charge is indeed the ratio of charge and mass, but since an atom is made up of neutrals and charged particles, you need to account for them. Thus, you'd use $$\eta=\frac{q\left(n_p-n_e\right)}{n_pm_p + n_nm_n + n_em_e}$$ where $\eta$ is the specific charge (my own variable, don't believe it's standard), $m_i$ is the mass of $i$ (neutrons, ...

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Conduction of charge has to do with the availability of electrons in the element to conduct charge by physically moving from one place inside the crystal structure of the material to another (that's what current is, movement of charge). Group I-III and transition elements conduct electricity. Moreover, they are solids so there is a high density of atoms per ...

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Well, in the case of hydrogen H1, the nucleus (which is nothing more nor less than a proton) can certainly be aligned by a static magnetic field -- said alignment being the basis of proton magnetic resonance, and, not coincidentally, most clinical MRI imaging. I won't venture beyond hydrogen, but that's one example at least.

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Yes. First, we could note that many nuclei possess nonzero magnetic moment. The presence of magnetic field may cause the change in its orientation and realign the nucleus as a whole. This is essentially the basis of Nuclear magnetic resonance. However, the orientation of individual nucleons relative to each other is not changed. Second, we could consider ...

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This is confusing enough to make me want to scribble down a few equations. This is a creation operator for deuterium: D_{\rho}^{\dagger}\left(k\right)=\sum_{\alpha\beta\gamma}\int\mathrm{d}^{3}l\mathrm{d}^{3}p\mathrm{d}^{3}q\delta^{\left(3\right)}\left(l+p+q-k\right)\ ...

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