# Tag Info

0

Tension is a concept which is introduced in physics. The molecular interpretation of the concept is not requited. Because it is complicated. Your preposition that the tension in the rope the summation of tension in the individual molecule is not correct an the molecular structure may not be linear. Direction of the tension force is always acting away from ...

0

Tension is a force transmitted by a rope. At an individual point in the rope, if the rope is stationary, there can be no net force so all forces cancel out. In a sense this means there is equal "tension" to the left and to the right; in that interpretation there is no direction (although I would normally say the tension is "along the length). When you have ...

0

The open boundary condition means, as stated in the question, that at the boundary no force acts on the end of the string in the direction of elongation. As the tip of the string has infinitesimal mass, we can argue as if we were considering conditions for static equilibrium (if the forces caused by the string would differ from the forces caused by the wall ...

1

The energy is reflected due to the discontinuity of the string mechanical impedance. Therefore it "can't be used as a part of the pulse" because it never gets to the denser rope. It's actually a special case of very general principle: whenever there is a discontinuity in propagation medium, energy reflection occurs. That's the same in optics, when you are ...

0

Well, since the resisting force is the same as the force applied in pulling the rope, then then the body will be in equilibrium. I.e acceleration =0... In the case of increasing force from 0 to X, there will be acceleration until the resisting force reaches the magnitude XN used in pulling the rope, which halts the motion of the body

1

Try to think the rope made up of small solid balls connected with springs. When you make the bump as shown in your picture the springs are expanded. Now you let go of it. The rising ball applies force upward to the ball on its right. The already expanded springs soon tend to decompress again. In doing so the the falling ball applies a downward force to ball ...

1

some of the tension goes into accelerating the pulley rotationally. Specifically $\Delta T \;R = I \frac{ \dot{v}}{R}$ Again you have to account for the mass moment of inertia of the disk. You could write $F_{net} = (m_1+m_2+\frac{I}{R^2}) a$ The masses do not rotate so their mass moment of inertia is of no use.

0

No, certainly not. In linear model there is something like static tension $T_0$ and time dependent tension $T'$. When there is for example a standing wave on a string with fixed ends, there is a minimum of string displacement (zero) but maximum of string tension $T'$ at the fixed ends. (As an effective value throught the time.)

2

Consider a small segment segment under tension From the balance of the horizontal axis you have $$-T \cos \theta + (T+{\rm d}T) \cos (\theta+{\rm d}\theta) = 0$$ $${\rm d}T \approx T \tan(\theta) {\rm d} \theta$$ Integrating by separation of variables $$\int \frac{1}{T}\,{\rm d}T = \int \tan(\theta)\,{\rm d}\theta + K$$ $$T = \frac{{\rm e}^K}{\cos ... 1 The pure simple harmonic motion is in real life very very rare. There are some cases which are really close (e.g. for engineering purposes). That might be: Small-amplitude oscillation of a mass on a spring (small enough for spring nonlinearities not to be pronounced) or other kinds of these simple or moreless model oscillators. Tuning fork. Strictly ... 2 For your example of a violin string, you can immediately determine that it is not simple harmonic motion by listening to it. Simple harmonic motion is a pure tone of a single frequency. Violins don't sound like that so you immediately know there are harmonics and it therefore is not a simple harmonic oscillator. As some other people have mentioned, a tuning ... 0 The frequency of a standing wave on a guitar string is given by$$f = \frac{v}{2L} where $v$ is the velocity, and $L$ is the length of the string. It can be shown by using the wave equation (which I'll skip, as it is a more complex derivation) that the velocity of a wave on a string is related to the tension in the string and the mass per unit length, ...

Top 50 recent answers are included