# Tag Info

## New answers tagged stress-strain

0

Correct me if i understood something wrongly.As i understand,you are asking why do we analyze using stress rather than forces? Well,stresses are easier to work with.Suppose we have a certain material with a cubic shape.A force is applied to it and so you make your analysis with the forces.ok,its all good.But when you want to make your analysis with a ...

0

Of course, I cannot be sure what you read, so, for what it's worth, Euler's buckling theory (http://en.wikipedia.org/wiki/Buckling#Columns )can also be relevant. It determines the maximum axial load a column can withstand without losing stability. I guess Euler derived the theory for a round column, but there should be formulas for an arbitrary shape of the ...

1

What you are looking for is the famous Theorema Egregium by Gauss, which asserts that the Gaussian curvature of a surface is invariant under local isometry. At the same time, the Gaussian curvature of a surface is the product of the principal curvatures. Regarding a slight bend along the middle as a local isometry (of course, this conceptualization breaks ...

-1

Pressure is perpendicular to the object, it is an external force only. Pressure causes stress inside of the object, so stress is an internal force.

0

The following is basically what the Ashcroft/Mermin says about it. The idea is as following: in harmonic approximation a relative displacement $u$ results in an energy $U=- \frac 1 4 (\vec{ u }(\vec R) - \vec{ u }(\vec R ')) \mathbf{D}(\vec{ u }(\vec R ') - \vec{ u }(\vec R))$ The tensor $\mathbf D$ already has natural symmetry ...

0

You should start with the strain energy density $\psi$, then define: $$C_{ijkl} = \frac{\partial^2 \psi}{\partial \epsilon_{ij}\partial \epsilon_{kl}},$$ and then define $$\sigma_{ij} = C_{ijkl} \epsilon_{kl}$$ The remainder of my answer will be about explaining why you have to do it that way. Firstly it is physical, there really is energy associated ...

1

Since $\epsilon$ is a symmetric tensor, it has 6 independent component that determine it. Hence use a multi-index $I\in\{(i,j)|1\leq i\leq j\leq 3\}$ to denote them. The strain energy density then becomes (perhaps one has to be careful with "diagonal" terms here in order to get the right coefficients) $$\psi = C_{IJ}\epsilon_I\epsilon_J$$ where summation is ...

Top 50 recent answers are included