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The shear modulus is a property of the material not of the shape the material is cut into. You normally see shear modulus explained using a cuboidal shape something like this: But this is just because it's simpler to explain. If a non-cuboidal shape is deformed the shear stress won't be constant but will depend on the shape of the object and the way the ...


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Yes, we can calculate the stress in the case you have given, and that stress is still given by F/A. Why is the stress for the case in which the wire is attached to ceiling at one end and pulled with a force F at the other also F/A? In the ceiling case, the net force is zero just as in your case. So the force exerted by the ceiling on the wire to pull it ...


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Hope this helps! The force of tension actually acts throughout the length of the wire from left to right keeping it together. It 'effectively' acts however, at the center of mass


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If the wire is ideal, the only force that can cause elongation is the net external force on the wire. i.e: mv^2/r + mg. Also however, the magnitude of net external force mv^2/r + mg is co-incidentally equal to net tension T just to keep the net force equal to zero. You say that the centrifugal force is the only force that causes elongation. But that would ...


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Obviously, the Tension is what always causes the elongation.Here at the lowest point, forces (under vertical equilibrium),(from wire frame of reference which is non inertial) net upward force equals net downward force T=mg + mrw^2 . Now if we look from outside the wire(inertial frame) then there is no centrifugal force .Here for the wire to rotate, the net ...


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I think you're talking about the shear modulus. (picture from the Wikipedia link above) If you take a block of some material and apply a sideways force $F$ the shear strain is defined as: $$ \gamma = \frac{x}{l} $$ The shear stress is the applied force divided by the area over which it's applied: $$ \sigma = \frac{F}{A} $$ And the shear modulus is ...



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