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This is really just an expansion on Alfred's answer (which is entirely correct :-). In most cases the only element in the stress-energy tensor that matters is the energy density, and for a body that can be treated as point-like this is the mass + the energy. You add the contribution of the energy by dividing it by $c^2$ according to Einstein's famous ...


2

I guess what i am trying to ask, is there any relation between energy and gravity? Indeed, the relation between energy and gravity is the core of General Relativity. From the Wiki article Stress-energy tensor: The stress–energy tensor (sometimes stress–energy–momentum tensor) is a tensor quantity in physics that describes the density and flux ...


0

Another way is the triple-right triangle: You move in a straight line for a long enough distance Turn right 90° degrees, walk in that same direction for the same distance Turn again to the right 90° degrees and walk again the same distance After this you'll end up at the starting point. This is not possible on a flat surface since you'd just be "drawing" ...


2

You've got the right idea, but, as pointed out in the comments, you've punched in the number for light years incorrectly. One light year is $9.461\times10^{15}$ meters. Also, you might not be converting km/s into m/s. Remember, all the units for a given dimension must be the same. Since you can look up this number, I don't think I'm giving anything away ...



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