# Tag Info

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It is only exactly at the critical temperature that this CFT result works. You haven't mentioned if you have used the critical temperature when you did the monte-carlo. At/near critical point, autocorrelation time becomes huge. (If I am not mistaken, autocorrelation time must blow up exactly at critical temperature, however it is cut-off due to finiteness ...

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Both temperature and pressure variation with altitude is given here You can use the ideal gas law to get the volume with altitude from these.

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The actual question in this question, is a good physics question. Freely interpreted, it basically asks if SR effects, in particular time-ordering of spacelike separated events, make it difficult or impossible to simulate physics. The answer to that is no. An "external" Simulator (be it a particle physicist or the hypothetical people simulating our ...

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USim can do vacuum + gas http://www.txcorp.com/home/usim/usim-overview. Not technically true vacuum, but 9 orders of magnitude density jumps. It doesn't support an incompressible fluid (liquid) though.

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You need a good kinematic solver, to get the axle position path. At any point you can find by evaluating the instant center of rotation of the rear triangle. For 1) and 2) the center is fixed as there is single pivot. For 3) and 4) they indicate a virtual pivot, which is incorrectly placed. In reality it lies on the virtual intersection of the upper and ...

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You need to start by writing down the equations of motion. These can be obtained solely from energy considerations using the Lagrangian formulation of classical mechanics. The suspension on the front fork should be relatively easy to account for, but the rear suspension could be more difficult since some of them have rather complicated geometries. If you ...

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Just use the free-fall equation. The time spent in falling from a height $h$ verifies this: $h - \frac{g}{2} t^2 = 0$ So you get: $g = \frac{2h}{t^2}$ Note that you have to determine the height $h$. How?, maybe you can estimate it thinking that the game's character is about 1.80 m. The $g$ you are obtaining here is the acceleration of the ...

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This answer is an complement to Chris White's answer. Fist of there is no explicit equations for the position of an object following a Kepler orbit as a function of time. However, when the initial conditions are known, the path the object will follow can be found, as well as the velocity, acceleration, ect. at any given position. This path can be described ...

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It seems you've done the hard part already, which is to evolve the object's position as a function of time. And moreover, the simulation seems stable over a number of orbits. (But eventually things start to go wrong; you may want to look at an answer I wrote to What is the correct way of integrating in astronomy simulations?) So my understanding is all you ...

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Orbital simulations can be handled by using the following relations: \begin{eqnarray} \mathbf F&=&m\mathbf a=m\frac{d^2\mathbf x}{dt^2}\tag{a} \\ \mathbf v&=&\frac{d\mathbf x}{dt}\tag{b}\\ \mathbf a&=&\frac{d\mathbf v}{dt}\tag{c} \end{eqnarray} The force acting on any two bodies, mass $M$ and $m$ is given by Newton's gravitational law ...

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Answer from 2C Solar: There are many 3D packages that render light aka raytracing, however most don't show the light itself. One very old method is POVray, started in 1991 and latest version 2013 The 3d package Spaceclaim can be used to create your laser / mirror model then export to POVRay where you need to define the properties. Bit of a learning curve ...

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Disclaimer: I updated my previous answer as I found a more accurate formula. The rotation angle $\theta$ is the angle between the vernal point and the meridian at Greenwich. This also corresponds with the Sidereal Time at Greenwich, converted to radians. For a given UTC time and a given date, the corresponding Greenwich (Mean) Sidereal Time (in hours and ...

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