# Tag Info

6

Backspin! Those shots in which the cue ball "draws" backwards after hitting the target ball involve backspin. Without backspin, the cue ball cannot reverse direction. Consider what happens when the cue ball is not spinning at all when it hits the target ball. The cue ball will come to a dead stop if it hits the target ball straight on. Think of Newton's ...

5

First of all, if the collision is elastic, the distribution of momentum in between the components is completely determined by momentum and energy conservation! This statement is most obvious in the center-of-mass frame where the total momentum is zero and the two objects are moving in opposite directions. The momentum conservation (the total momentum is ...

4

If you frequency analyse the sound from your equipment then the fundamental frequency will the same as the rotational frequency. You could record the sound and use some software like Audacity to do the frequency analysis. This is exactly what alemi did in his reply to Can I compute the mass of a coin based on the sound of its fall?. Alternatively, and ...

2

You seem to be saying that friction couldn't speed it up, because nothing else is moving that fast. Well, how fast is it moving? We can imagine the gyroscope axis parallel to the z axis, and the casing to be aligned such that the x axis goes through it. If the casing is tipped slightly, the gyroscope resists that turning and one side of the shaft has firm ...

1

You are very close. Just to review what is going on, the period is given by $$T = \frac{2\pi}{\omega} = 2\pi \sqrt{\frac{I}{k_{eff}}}$$ where $I$ is the moment of inertia of the system and the torque is proportional to the angle by which the pendulum has been displaced with a coefficient that I'm calling $k_{eff}$ in analogy to ...

1

By way of analogy, think of what happens when you blow up a balloon and let it go. It spins around, goes this way and that. A balloon rarely goes straight, without spinning. The thrust from a balloon rarely goes through the center of mass. It rotates and translates. Because the thrust vector itself turns with the rotating balloon, the translation is not ...

1

There is 1 reason; Newton's third law. When you fire a bullet, the bullet has a momentum in one direction (east) and the gun has momentum in the opposite direction (west). Of course, the person stops the gun from moving. When the bullet strikes an object, it imparts its momentum on the object. Neglecting air resistance, it is easy to show that all the forces ...

1

looking to the doppler effect: frequency equals (the speed of sound in what ever temperature air you are in: $c$)+(Velocity of you relative to the measured object: so if you are stationary this value is zero: $V(r)$)/(speed of sound in what ever temperature air you are in: $c$)+(Velocity of object relative to you $V(s)$: essentially the speed of the object ...

1

This sounds to me like an experimental question (but be careful not to hurt yourself!). Note that since you want the chair to rotate forwards towards the ground, you'll want to consider the direction of the angular momentum your motion introduces. If you kick your legs out rapidly, not only does the weight of your feet tilt the chair forward, but the ...

1

Here's my explanation (hopefully it's right but I'm no expert): Consider the simpler example of pushing a really heavy box; if we push on it there's a static friction force, but if we don't push on it there's no force. Similarly for a cylinder on a horizontal plane, if we push on it the static friction force causes it to rotate, but when we stop pushing ...

1

The direction the ball will take depends on the angular momentum. The velocity with which the ball moves or bounces backwards but the chief determinant is the spinning effect of the incoming ball.

1

There is a distinction between points and vectors. Points are positions in space, and vectors are directions. One can easily mix up the two, because in Euklidean space they look rather similar. $\theta$ in this case is a coordinate, i.e. part of the description of a point. The vector associated to that coordinate could be called $\hat{e}_\theta$, and point ...

Only top voted, non community-wiki answers of a minimum length are eligible