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1) first thing you have to notice is wind loads on panels is far more than dead weight of panels 2) so the torque required mostly depends on peak wind load. 3)It also depends on friction in bearing. 4)Finally the weight of the panels should be considered, lower the moment of inertia about rotational axis, lower the torque required.


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I'm not knowledgeable in some aspects of the question, but I will provide an answer unrelated to others. An object can rotate so fast that some representations of angular velocity cannot be valid. For example, when an object rotates more than 180-degrees or 360-degrees (pi or 2*pi radians) per unit time, the representation must be able to represent such ...


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I am not a physicist (my background is biotech) but from a non-technical perspective I believe that since the centrifuge has no gravitational field (it operates in the same part of earths gravitational field as the observer) then the only time dilation that might be measured would be due to the velocity of the test subject rather than the g-forces created by ...


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I put a cesium clock in a centrifuge for 24 hours, got 45.9 microseconds first relative to gps satellite. 20,200km up Centrifuge spun at 2 G's it was 91.8 microseconds. You can suck on numbers all you want, but experiments don't lie.


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The units of $\hbar$ are in fact J.s/rad. (thanks AV23) this is because $\hbar = \frac{h}{2\pi}$ the units of h are J.s and the units of $\pi$ are rad. Thus we have J.s/rad. (thanks Noiralef) Thus the ladder operators are in fact unitless. On reflection this is the only logical possibility as they move between different eigenstates - which must all be in ...


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You want to consider the following factors: Maximize initial energy stored in the rubber band. This means you need to be able to twist the band lots of times, and as it unwinds it must continue to produce torque. Minimize internal friction - make the mechanism that converts power from the band to kinetic energy as "direct" as possible. In fact a rubber ...


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... Another way to look at it is to use geometry which includes the vertical time axis, the horizontal space axis, and the stacking of both motion vectors( c, v ) and length scalars. Rotation determines the direction of travel in space-time, thus determines the velocity across space and the rate of the ticking of time. Here, twin spaceship A is a rest in ...


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You probably already understand that merely rotating a coordinate system does not change the physical system you're modeling. Given one set of axes, any rotation of those axes just represents some freedom of choice to do math how you see fit. So with that in mind, if you were pointing northeast (and chose a pair of coordinate axes to point northeast and ...


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Bernhard Schutz discusses this reasonably well in his book A First Course in General Relativity. Consider sending a light beam horizontally along an $x$ axis and then receiving it back again. A space time plot of this would look like Here's an example of the rotation you are describing And this is how everything becomes distorted when you create such ...


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The stroboscopes we had at school, in a largely pre-electronic age, were simply rotating discs with a hole near the edge. You shone a light at the edge, and the RPM of the disc determined how rapidly the strobe would flash (as the hole passed in front of the light).


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Since the mass is at equilibrium, the force due to rotation which depends on $m,\omega,r$ acting in the radial direction should be equal to the force due to the spring which depends on $k$ and $x$. The springs can be thought to be composed of 2 springs in parallel. Equate them to find $x$


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I won't give you the answer but to get you started, use Hooke's law and the centrifugal force expression in terms of the angular velocity ω. Remember: The centrifugal force depends on the distance of the mass from the axis, x The restoring forces provided by each of the springs are actually the same as each other since one is compressed and the other ...


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It comes from the fact that most strobes are, or were, used to examine car engines. Specifically the distributor. Hence RPM



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