New answers tagged

0

This is like a driven harmonic oscillator problem where driver is the tuning fork. If the sound box have same frequency as of tuning fork the energy stored in tuning fork will quickly transfer into sound box, then it will dampen subsequently and that is the reason for faster damping. On the other hand if you provide energy to sound box then the sound box ...


1

The answer has pretty much been given in the comments, but I think a nice pictorial representation might help. The mathematical form of a standing wave is $$y(x) = \sin \left(\frac{2 \pi}{ \lambda} x \right) $$ Here $y(x)$ is the displacement of the string at point $x$. If we plot the waves for the four wavelengths we obtain the following picture I will ...


0

Lord Rayleigh's explanation is classic and is basically correct, but if you research further you'll see allot of debate and other explanations as well. You can create the thermoacoustic resonance by even simpler means than a metal tube and gauze. You don't necessarily need the gauze and can cause the resonance with just a flame and a cardboard tube as I did ...


1

I stumbled upon an explanation of the Hoot Tube on Wikipedia. But until now I've never heard it referred to as a Rijke tube. It looks like this is the mechanism I was looking for -- "The sound comes from a standing wave whose wavelength is about twice the length of the tube, giving the fundamental frequency. Lord Rayleigh, in his book, gave the ...


1

Since you want to find the maximum R, you must differentiate R(ω) with respect to ω (that is dR(ω)/dω ) and then set the derivative equal to zero to find at which value of ω you have a maximum (be careful not to accept negative values or zero). Then insert that value of ω into the response amplitude equation to find your maximum. Hope it helps!


0

The resonant frequency is equal to the natural frequency when no damping and no external force at all is applied to the system. When damping is applied so that now the decay time (decay of amplitude) is in effect, the resonant frequency decreases a little below depending on magnitude of damping.



Top 50 recent answers are included