# Tag Info

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Reflection polarizes light. A reflected ray becomes linearly polarized perpendicular to the plane containing the incident and reflected rays. This is why polarized sunglasses are effective for reducing glare. The autofocus may not be working as expected because much of the scene is polarized light.

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Assuming the surface of the metal remains smooth, the reflection from it will be specular and the metal will look shiny regardless of the temperature. However the amount of light metals absorb, instead of reflecting, generally increases with increasing temperature because you get more scattering of the conduction electrons by lattice vibrations. So the metal ...

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It depends where the aluminum foil is situated. For example I use aluminum foil behind a wood stove to reflect the heat to the room instead of heating the wall. So, does it mean that a more shiny aluminium foil will reflect more light and thus make the room more cooler as compared to less shiny foil? You can see from Crazy Buddy's answer that the more ...

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First, there's no perfect reflector nor absorber. In fact - even Aluminium does absorb some radiation (by which it gets heated, can be noticed at incident high frequency radiation). One more thing is that aluminium foils are designed in a way to reflect light. Here's the Wiki article quote... Aluminium foil has a shiny side and a matte side. The shiny ...

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The phase change happens because it is how waves behave. An additional link provides lecture notes. I know that u are not satisfied with this answer but you can compare this with mechanical waves in a string which gives better intuition by use of newtons laws.

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The answer is this: You will need to cover the item you don't want to heat with a conducting material, creating a so called Faraday's cage, which is connected to an earth potential equal to the potential of the metal casing of the microwave oven. The reason for this is threefold: The covering material needs to be a conductor, because conductors have the ...

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Assuming mirror to be spherical section. C is the center of sphere. See, Using trigonometry. $$x=d \times \sin(2\theta)$$ $$x=R\times\sin\theta$$ Eliminate $\theta$ and get $d$ : distance from Center of curvature as a function of $x$. Verify for small theta where $\sin\theta\approx\theta$ If you just want to see that which side ray bents then see. ...

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A parabolic mirror is a special case of a concave mirror. The rays at the rim are refracted to the focal point. This is true in simplification of geometric optics and perfect manufactured mirror. However in modern techiques like injection molding there are more imperfections at the rims of mirrors. The question of a general concave mirror can be answered ...

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You find $s$ in the same way you found it for concave mirror, just keep in mind that for the convex mirror the image is always virtual(as explained nicely in the Wikipedia article on curved mirrors, it cannot be projected on a surface, unlike the real image), so in this case (by convention) $s'=-35cm$ and $f=-53cm$.

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This follows from from Fermat's principle. A derivation for the reflection is e.g. found here.

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Yes... your supervisors formula is incorrect. Smart people make mistakes -- it happens. If your supervisor isn't open to criticism, then I suggest that you give him or her a few simple examples that illustrate the problem, and then immediately present a solution. Your example of a mirror coated over a non-mirror is a great place to start. In order to solve ...

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