# Tag Info

OK so it's not a question of normalization. My confusion arose because of naïvety. $$\tag{1} u^{(r)\dagger}u^{(s)} = 2E\delta_{rs}$$ $$\tag{2} {\bar{u}^{(s)}}u^{(s)} = 2m.$$ Since the normalization relations $(1)$ and $(2)$ applies to same momenta spinors i.e. $\bar{u}(p)[\cdots]u(p)$ and so on. If one is not as lazy as me, one can easily derive the ...