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It should. In free space, separating charges ('polarization of charges') in this manner would result in creating an electromagnetic wave. The particular frequency of the wave, and whether or not it can continue to propagate are contingent on the situation (how fast you separate the charges, what the medium is). Thanks. I had never considered the Hall ...

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Birefringence. Many substances such as cellophane or antistatic tape have two indices of refraction, a 'fast' axis, and a 'slow' axis, not necessarily at right angles to each other. Minute changes in the thickness of a birefringent material will appear to produce different colors between crossed linear polarizers because different thicknesses of ...

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Optical systems not involving magnetic fields are symmetric. So, if the display passes light in one direction, it will pass light in the other. Putting a mirror at the back of the TFT and lighting it from the front is therefore equivalent, expect that some light will be attenuated on the way in as pointed out by @CarlWitthoft in the comments. As a ...

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A quick Google search led me to this 2010 paper by Rizzo et al (that's arXiv link, here's the IOP science link). The article states, ...the inverse Cotton-Mouton effect (ICME in the following), [is] a non linear optical effect that in principle exists in any medium. In the presence of a transverse magnetic field, a linearly polarized light induces a ...

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Simply, at Brewster's angle, the $\pi$ - component of incident electromagnetic wave always transmits 100%. What is left is the $\sigma$ - component. The $\sigma$ - component of EM wave (which is already lying in xz - plane) striking on the second plate with respect to that plate is equal its amplitude times cosine of the angle the glass plate B will rotate. ...

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The reflected light off of the second Brewster window will be maximum in the configuration shown. It will be a minimum if you rotate it by $90^\circ$ around the $z$ axis. For angles in between it will act just like any other pair of polarizers.

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With circularly polarised waves, the effect can only be observed interferometrically, because the Faraday rotation simply becomes the imposition of different phase delays on the two circularly polarised components. To understand this, witness that the Faraday rotation on a general polarisation state expressed with linear polarisation state basis is: ...

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