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What you need to pull an object off the surface of another, gravitationally, is for the tidal acceleration $F_{\rm tidal}$ from the "external" body at the surface of the Earth (or whatever other body) to exceed the gravitational acceleration $g$ of Earth on the surface. This comes with the caveat that if the tidal forces are too strong, they will start to ...


Assuming that the gravity well acts as an attracting mass whose force follows Newton's law of gravitation, your well will suck the object from Earth's surface when the force from the well is larger than the force from the earth. That is, $GM_{earth}m/R_{earth}^2<GM_{well}m/r_{well}^2$, where $r_{well}$ is the distance between object and well. Earth ...


No - any simultaneous rotation on multiple axis is identical to a single rotation along another axis. It is similar to moving straight along two different vectors at the same time - that is just a movement along a new (combined) vector. The same is true for rotation, it is just not as easily imaginable.


You can calculate the volume from the information given about the radius, assuming the planet to be spherical of course.

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