# Tag Info

## Hot answers tagged photometry

3

Yes it can be seen, given that you do not get much noise and that your sensor is sensitive enough for it to be able to detect the signal. As you have not specified anything about the light not much can be concluded, more than that it depends on the sensor, the transmitter and the noise from everything else.

2

I believe (as per John Rennie's answer) that $\mathrm{J}$ in this case does not stand for Joules. The Wikipedia page for the International System of Units (SI) makes a distinction between "unit sybols" (the familiar $\mathrm{m}$ for metres, $\mathrm{J}$ for joules, etc.) and "dimension symbols". The difference is that there are dimension symbols only for ...

1

$\mu_{B}$ is surface brightness of an extended source in the B-band. This is given as (apparent) magnitude per square arc seconds. You need to calculate the area you observe at the distance R through an angle of 1 X 1 arc seconds. With some trigonometry applied you will get; $$A = 4 R^{2} \frac{1 - \cos \varphi}{1 + \cos \varphi}$$ Where the angle is 1''. ...

1

From the Wikipedia link you posted, it looks like CIE Standard Illuminant D65 does not exactly model a black body spectrum. Look at the animation in the second figure. The red line is a perfect black body spectrum and the black line is the D65 one. I believe this is because the purpose of D65 is to represent the spectrum of daylight on an average day at ...

1

I don't know much about observational stuff, but since you haven't gotten any answers I thought I would chip in what I could... The error of the raw flux will be based on poisson noise from the signal, and complex read-out/detector noise from your instrument. The latter should be documented by the manufacturer. The former you can calculate based on the ...

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