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Your Speculation 1 is not really true, whereas what you consider in Problem 1 is correct. The probability of a photocathode to emit an electron upon incident photon is called quantum efficiency. Contrary to your intuition, it is relatively constant for the range of wavelengths to which the photocathode is sensitive and it drops quickly outside of this ...


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I'm going to have to give an answer that's very different to Jimmy360's. Apologies. How does the potential and kinetic energy of a photon relate? They don't. The photon is all kinetic energy. Do they mean the same thing? No. When you drop a brick, its gravitational potential energy is converted into kinetic energy. When you dissipate this kinetic ...


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Quote from a webpage a bit over my head :-) greatians.com Photon has linear momentum. Photon travels in vacuum space at the ultimate speed of light. Photon has the quantized energy of hf as given by eq. WD.1.2. E = hf … eq. WD.1.1 where h = Plank’s constant ...


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Imagine a beam of light, going towards a massive object. It has potential energy in the gravitational field. Of course, the potential energy has to become kinetic energy. This is done by shifting frequency. The energy of a photon is given by $E = hf$ so to increase kinetic energy we must increase frequency. If the beam of light was red, it will be a higher ...


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This is I guess a common problem that stems from the way we use the word "intensity". Normally, we would use intensity to mean something like the energy going through a unit area per unit time. In the case of the photoelectric effect, we instead generally mean the number of photons (per unit time), as it is this that decides how many photo-electrons are ...


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Time varying intensity means time varying flux of photons. Above threshold this gives a consequent time varying photocurrent at anode. This is the basis of optical sound since the 1920's, where the intensity of light was modulated by the varyng transparency of the soundtrack on the film and then read by a phototube. Below threshold: as already answered, very ...



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