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2

Consider a variant of the FitzHugh–Nagumo system: \begin{align}\dot{x} &= x (a - x) (x - 1) - y \\ \dot{y} &= bx - cy \end{align} with parameters like $a=-0.02; b=0.01; c=0.02$. The eigenvalues of the Jacobian at $(0,0)$ (which is a fix point) are $±\frac{\sqrt{6}}{25}i$. The attractor for this system looks like this: Obviously, this is ...

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The melting point of nitrogen is greater than that of oxygen. Is gaseous oxygen really liquid oxygen dissolved in gaseous nitrogen? No. It is gaseous oxygen. "Water vapour in the air" (your phrase) is just that - vapour. Not liquid droplets "dissolved" in air. You may be confused by the fact that wet steam does contain water droplets, and the steam from a ...

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The specific volume may vary, but the material still will be at triple equilibrium. In other words, specific volume is not an intensive variable that determines whether or not the material is at its triple point. Notice in the 3-D phase diagram that the triple line is at one pressure and one temperature. It is the boundary between liquid + gas and solid + ...

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Because specific volume or specific dipole moment, or specific "anything" are not really intensive parameters. What is a "true" intensive parameter for which the Gibbs rule holds, and what is only a "specific anything" intensive and there Gibbs does not hold, can be seen only in their relationship in the energy variation equation of state: \$dU=TdS-pdV+\mu ...

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