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Consider an arbitrary point P and a point close to it, let's say A. $\underline{g}_P = -\frac{GM}{r^2}$ Whereas $\underline{g}_A = -\frac{GM}{(r+a)^2}$ Taylor expansion on $\underline{g}_A = -\frac{GM}{(r)^2}(1-\frac{2a}{r} +...)$ Finding the difference between $\underline{g}_P$ and $\underline{g}_A$ yields $\frac{2aGM}{r^3}$ note that this answer ...


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As I understand it, a tide is basically a wave with a wave-length = 1/2 the circumference of the earth. The peak to trough is 1/4 the circumference, see pretty picture: That's why lakes don't have measurable tides. The east to west distance isn't sufficient on lakes. Only oceans have significant tides. The Pacific is already large enough to have a ...


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If the moon is on the opposite side of the planet while the sun is over our heads, I would be under the impression the moon pulling the atmosphere towards it would allow warmer days or cooler nights as the atmosphere is thinner during this time.


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If someone (like superman) could stop the moon from its orbital motion then yes it would fall towards the Earth. Only then the direction of motion would be parallel to gravity. Same with the I.S.S or the satellites orbiting Earth. They could also spiral in and crash because the atmosphere is taking away their kinetic energy. Just like the comment says ...


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It depends on, what consider we significant. On our current best hypothesis, the moon was created by a collision of the Earth and a Mars-sized planet. Thus, the core of the Moon contains much fewer heavy elements, and thus also much fewer Uranium and Thorium. This corresponds also the fact, that themean density of the Moon is only 3.3, while the Earths is ...



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