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The maximum acceleration experienced by your accelerometer (assuming that it does not automatically zero out the acceleration due to gravity) will be the same as the maximum acceleration experienced by any other object in the helicopter, as long as the helicopter attitude is maintained (no rotation). You would simply take the instantaneous acceleration ...


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I try to measure the energy and the position of the system simultaneously The states with definite energy are not states with definite position so there is no particle state of both definite energy and definite position.


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At the first look the question seemed very interesting, but later I found the mistake. You said you are measuring the position of the particle precisely. But how? You can tell that the particle is inside the well but you can not know the exact position of the particle. For more info read ...


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If you are considering a system of a single particle in a potential well with infinitely high walls and with finite width, the energy operator is $ H = \frac{p^2}{2m} + V(x) $ where $ V(x) $ is the potential energy operator, vanishing inside the well and infinite outside it. Being that $ \frac{p^2}{2m} $ does not commute with $ x $, how are you saying that ...


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You may be aware that both torque and angular momentum can be represented as a vector - and that such vectors follow the normal rules of vector addition. Thus, if you have equal rotation about both the X and the Y axis, what you really have is rotation about the XY axis; and in general, rotation about an arbitrary axis can be projected onto the X, Y and Z ...


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I've come to the conclusion that the language used in the paper is probably not completely accurate. The paper mentions determining displacement based on "reflection time." I believe that the device actually uses trigonometry and the angle formed by the bounced laser beam to determine the displacement of the torsion pendulum. The angle is measured using a ...


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Can you cite the paper, please? Assuming that it's a modern version of an old experiment, my first guess would be, that the observation uses the fact that the light will induce a constant moment on the torsion pendulum. The response of the pendulum will be an oscillatory motion, for short amounts of time (seconds to minutes), that motion around the original ...


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The easiest way to make a suitable coil is experimental. After all, what you want is not a precision measurement of the magnet, but all you want is to generate the necessary electricity for your LED and you don't need any math for that. Simply make a coil that satisfies your geometry out of some wire with reasonable resistance. In this case, I would estimate ...


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You provided already the most important answer, saying “Time is just …” You are right: time is very much over-estimated. Time is just and nothing more than aging of matter (proper time of matter), every mass having its private time which may be observed by anybody else. You will hear many other things about time, but without any proof, without physical ...


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Philosophically, both time and distance are illusions. Distance is actually more disturbing than time. So first, let's define what "time" is. It is the number of transitions of an atomic state (see atomic clock wiki). Distance, a meter, is defined to be the length a photon (light) travels in $\frac{1}{299,792,458}$ of a second (source) which ...


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The elasticity does not influence the measurement as long as the scale stands perfectly level and you stand perfectly still. The angle of the floor however can greatly influence the result. Your gravitational force won't compress the spring in full strength, it will rather split into normal force and downhill force. The spring will only "see" the normal ...


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If you measure the absorption of microwaves by a gas of caesium atoms you'll get a spectrum looking something like this: NB not a real spectrum - I drew this as an illustration When the microwave frequency is 9,192,631,770 Hz the microwave photons have exactly the right energy to flip the outer electron spin, so at this frequency they are more strongly ...


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It does not mean that it switches the hyperfine state that often. I means that, if you hit the atom with a photon that (by $E = \hbar\omega$) corresponds to exactly that frequency, then the energy of that photon will precisely be the energy to lift the electron from the lower hyperfine state to the upper hyperfine state. If hit, it will then, as with all ...


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Regarding your new formulated question "my question boils down to whether a device similar to a voltmeter or thermometer exists for entropy": Well in that case then the answer is no, you can only measure entropy by studying the change of its dependencies on extensive/intensive variables that influence it (as they are different in different systems). To make ...


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I think a ferrite rod antenna in a radio receiver is an example where the magnetic component of an EM-field is picked up.


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We do not use just the electric component, this is not possible. An EM radiation is an oscillation in media or void of electric and magnetic fields. As described by Maxwell equations, the electric field oscillation generating the magnetic one and vice versa. So is kind of an electric wave and a magnetic one co-dependent with each other. It is true that we ...



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