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One way is to connect the ignition to a high voltage (10kV) capacitor. Then the energy is: $$E = \int VI d t = \frac{CV^2}{2},$$ where $C$ is its capacitance and $V$ its voltage, assuming that you connected it and did the measurements so that energy losses are negligible.


Yes. The suit is of a conducting material and charge thus moves inside the suit material much more likely than through the content (the person) inside the suit.. This is called a Faraday cage and is an effective shielding mechanism from electric shocks. Excess charge will stay on the outer surface of a conducting object and charge will redistribute on the ...

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