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Both isotopes are isovalent so electronically they are identical (in essence your not going to get that much difference in bond angle). However in the asymmetric well approximation since deuterium is heavier the $D-O$ bond is lowered down the well i.e. it has a lower ZPE than the $H-O$ bond and is therefore a stronger bond. This means it has a smaller ...


According to http://www1.lsbu.ac.uk/water/data.html (and with reference to A. G. Császár, G. Czakó, T. Furtenbacher, J. Tennyson, V. Szalay, S. V. Shirin, N. F. Zobov and O. L. Polyansky, On equilibrium structures of the water molecule, J. Chem. Phys. 122 (2005) 214305), the bond angles H-O-H and D-O-D are pretty much the same - 104.50 and 104.49 deg., ...

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