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16

These are all good questions. Perhaps I can answer a few of them at once. The equation describing the violation of current conservation is $$\partial^\mu j_\mu=f(g)\epsilon^{\mu\nu\rho\sigma}F_{\mu\nu}F_{\rho\sigma}$$ where f(g) is some function of the coupling constant. It is not possible to write any other candidate answer by dimensional analysis and ...

8

The easiest way to see imaginary time used is in elementary quantum mechanics in one dimension. (This is the explanation cribbed from wikipedia). Suppose we're looking at a tunneling-through-a-barrier problem. We start with the Schrodinger equation: $$-\frac{\hbar^2}{2m}\frac{d^2\psi(x)}{dx^2}+V(x)\psi(x) = E\psi(x)$$ Make the ansatz $$\psi(x) ... 5 The reason why classical solutions add a "lot" to the path integral is that their action (phase) is stationary i.e. almost the same phase as the action (phase) in their reasonably large vicinity of the configuration space; one gets positive interference as a consequence. More generic paths cancel with the adjacent ones whose phases are different and random. ... 5 Let us look at the instantons of an ordinary pure Yang-Mills theory for gauge group G in four Euclidean dimensions: An instanton is a local minimum of the action$$ S_{YM}[A] = \int \mathrm{tr}(F \wedge \star F)$$which is, on \mathbb{R}^4, precisely given by the (anti-)self-dual solutions F = \pm \star F. For (anti-)self-dual solutions, ... 4 A soliton is a localized, non-dispersive solution of a nonlinear theory in Euclidean space. It certainly is a real object: you have a famous story about a certain John Russell who observed soliton-like waves made by a boat on a river (wikipedia knows everything about it!) The so-called morning glory clouds in Australia ... 4 It's Stokes's theorem. Consider a field F = dA + A \wedge A such that A is pure gauge at infinity, that is, \lim_{x\to\infty} A(x) = \omega\, d \omega^{-1} for some \omega : S^3 \to SU(2) \sim S^3 where \omega is a function on the 3-sphere because the limit can depend on the direction out to infinity. In differential forms the first expression is ... 4 I) This is discussed around eq. (23.7.1) on p. 462 in Ref. 1. The task is to perform the path integral$$\tag{1} \int_{BC} [d\phi]e^{\frac{i}{\hbar}S[\phi]} ~=~\sum_{\nu}\int\! du \int_{BC_0} [d\phi_q]e^{\frac{i}{\hbar}S[\phi_{cl}+\phi_{\nu,u}+\phi_q]} $$over fields \phi with some (possible inhomogeneous) boundary conditions BC. This is done by ... 4 I will add to twistor59 answer. Hawking liked the concept of imaginary time \tau=\mathrm{i}t because it transforms a Lorentzian metric$$ds^2 = -c^2 dt^2 + dx^2 + dy^2 + dz^2$$into a four dimensional like Euclidean metric$$ds^2 = +c^2 d\tau^2 + dx^2 + dy^2 + dz^2$$Hawking and others believed that a quantum gravity theory could be developed in this ... 4 For the pure e.g. d=4 gauge theory instanton and gauge field perturbations around it, there is no negative mode – the counterpart of the bound state. It's the only one among the 3 classes that is absent here. One may see this absence by noticing that the gauge theory may be embedded into a supersymmetric theory with the same gauge-field degrees of ... 3 Instanton calculations involve integrals over collective coordinates. One of these is the instanton size \rho. Reliable instanton calculations are those for which the integral over instanton sizes is dominated by small sizes so that (for asymptotically free theories) the coupling constant is small and higher order corrections in the semi-classical ... 3 This is apparently too long for a comment, so it's going to be fleshed out into at least (hopefully) a partial answer. A big problem I see with this is determining which theories can live in the same universe. In this way, I think Liang Kong's Mathematical Theory of Anyon Condensation provides a way forward. To reconstruct your set up: Consider three ... 3 Fermionic zero modes on an instanton background are in one-to-one correspondence with solutions to the Dirac equation$$(i D_\mu \gamma^\mu - m)\Psi = 0$$where the partial derivative D_\mu contains the gauge field term with the gauge field defining the instanton solution substituted into it. We want to study these solutions in the Euclidean spacetime. ... 3 Yes, you can recover the Seiberg-Witten prepotential from the Darboux coordinates X_\gamma (and indeed also from their "semiflat" versions X_\gamma^{sf}). The reason is the asymptotic property X_\gamma \sim exp(\pi R Z_\gamma / \zeta) as \zeta \rightarrow 0 (up to a \zeta-independent constant). Thus knowing X_\gamma is sufficient to recover ... 2 TO have an instanton solution, you need to map the (euclideanized) "spacetime at infinity" to the group manifold. In the case of SU(2), both the spacetime at infinity and the group manifold are S^3 and instantons are characterized by the integers. I hope you understand that much, at least for SU(2). If you're interested in 4d instantons, they are ... 2 1) If \phi is non-singular, you can safely multiply both sides by \phi and get \square \phi = \phi*0 = 0 . If \phi is singular you can't do this because \phi * 0 is undefined. Equivalently, where 1/\phi=0 you can have \square\phi nonzero, as shown in (4.64). The singularities in \phi will map to zeroes in 1/\phi. 2) I believe only the ... 2 I'm not sure why you are asking, because you seem to mention the answer already. This problem has been studied thoroughly in the late 70's by Belavin et al and 't Hooft. As far as I understand, the quantum vacuum is the lowest energy eigenstate of a Hamiltonian. It turns out that the classical solutions to the equations of motion (of a particle, or a field) ... 2 Where a string carves out a 2-dimensional world-sheet and a point particle carves out a 1-dimensional world-line of spacetime, the instanton carves out a 0-dimensional world-point. Counting only spatial dimensions, a string is 1-dimensional and a point particle is 0-dimensional. By logical extension, an instanton has dimension -1, if we only ... 1 1) NO 2) The usual way of doing it is to first solve the instanton solution in euclidean time, which is equivalent to obtaining soliton solution of a given potential. Since you have read the book, I am not going to explain how it is done for this case. Then, plugin your instanton solution to the euclidean action and evaluate it. Since ... 1 Let me first refer you to three references pedagogically treating Instantons in quantum mechanics: 1)Riccardo Rattazzi's lecture notes treating instantons in nonsupersymmetric quantum mechanics. In these notes the anharmonic oscillator model is elaborated with great detail 2) Philip Argyres lecture notes treating instantons in supersymmetric quantum ... 1 There seems to be a slight confusion about the meaning of solution: The principle of least action leads to the equation of motion (Euler-Lagrange equation), which correspond to a minimum of the action functional. These equations can have multiple solutions, so there is no contradiction in the formalism. There can multiple solutions that minimize the energy, ... 1 The usefulness of Wick rotation lies in the convergence properties of the path integral. If you look at the integrand of the path integral in Minkowski space,$$\int\mathcal{D}\phi\;e^{iS_M},$$you can see that it is an oscillating function. The integral of an oscillating function can in general be considered problematic. Wick rotation, which is ... 1 I think the path-integral is a complete red herring here! I'll try to convince you that Wick rotation yields completely equivalent way of writing the Lagrangian in classical field theory. Consider a classical action$$S[x] = \int L[x(t)] dt where $x:\mathbb{R} \to \mathcal{M}$ for some target manifold $\mathcal{M}$. The Lagrangian is schematically given ...

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Well, besides time translation invariance, it is important that the action $S$ admits instanton solutions $\bar{x}$ in the first place. (This is the case for the double-well potential that Coleman is analyzing in Section 2.2 p.270.) In the $T=t_f-t_i\to\infty$ limit, again because of no explicit time dependence, these instanton solutions must be parametrized ...

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Let'me just sketch an idea to inroduce "imaginary time" . A photon in a black hole or in a singularity, has to disappear, it is energy should be 0. If that photon had a previous existence, the black hole has to distruct its energy: $E, A$, or its energy $a+a-=\left(N+\frac12\right)h\nu$ The simplest way is to consider the phase factor of the ...

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