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Expanding on Jan Dvorak's comment: When you change the magnetic field inside a loop, an emf (electromotive force) will be generated. Now if you have two loops, each of these will experience the same e.m.f. When you put them in series, you have a coil with two loops, or two coils with one loop. No matter which way you look at it the voltage across them ...

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Here's a brief 'classical' description: In 1820, Hans Christian Ørsted discovered that an electric current through a wire sets up a 'magnetic field' around the wire, in concentric cylinders with the wire as the axis. In its simplest form, an 'inductor' is just a piece of wire. For this reason, a DC voltage applied across an inductor is like a 'short ...

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The 'self-inductance' of a transformer is the net inductive effect transformer windings reflected on the primary circuit. Both primary and secondary windings of a 'real' transformer exhibit some electrical resistance due to copper losses in the windings and inductance due to magnetic flux 'leakage'. Although most of the magnetic flu is confined to the core ...

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Forget for a moment the secondary coil. Then you do indeed get an EMF as you describe. This is called an inductor, and it's hallmark is that current and voltage are out of phase by 90 degrees, i.e. the voltage drop across the inductor is $L \frac{dI}{dt}$. This does not ruin the transformer, as you say, because it merely means that if the voltage across the ...

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I already got the answer. because transformers simply doesn't work in high voltage environments. High voltage environments causes dielectric breakdown which reduce the transformers function which is bad. Tesla coils fix this problem.

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On one hand, the flux $\Phi$ seen by the solenoid is $n*\phi$ where $n$ is the number of turns and $\phi$ the flux seen by each turn. I think this is straightforward : if there are two turns, the flux is counted twice. On the other hand, the magnetic flux induced by one turn is $B*S$ or ($\int \vec{B}.d\vec{S}$). The flux of two turns is twice the flux of ...

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