# Tag Info

## New answers tagged imaging

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I'm not sure exactly what you mean butYou get a virtual image from the main mirror surface, but you also see another virtual image a little nearer to you (by an amount equal to twice the mirror's thickness) than the main one. This Fresnel reflexion has intensity $\left(\frac{n-1}{n+1}\right)^2$ times the incident wave one, where $n$ is the glass's refractive ...

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