New answers tagged

0

The complexity of the molecule, compared to H2 and O2, makes its thermodinamical properties completely different, up to the point that it is even in a different phase at room temperature.


0

$\langle z\rangle=\int_0^\infty r^3dr[\int_0^{2\pi}d\phi\int_0^\pi \sin \theta \cos \theta d\theta]=0$ As the $\theta $ integration is zero. But the symmetry argument is clear if the integration is written is Cartesian coordinates.In that case $$\langle z\rangle=\int_{-\infty}^\infty \int_{-\infty}^\infty \int_{-\infty}^\infty z dz |\psi|^2 dx dy$$ As you ...



Top 50 recent answers are included