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What might help (or not) here is to distinguish between reference polarity and absolute polarity. When you label one terminal of the inductor with a plus sign, you're simply choosing a reference polarity. You are, in essence, choosing which end to place the "red lead" of your voltmeter. If you calculate that the voltage across the inductor is negative ...

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Work is described by the following formula: $$W=Fs$$ with $s$ is the distance, 40 m in this case. $F$ is force, in this case work is done against gravitational force, so $$F=mg$$ $m$ is the liquid mass and $m=\rho V$ $\rho$ is the liquid's density, $V$ is the liquid's volume. $$W=\rho Vgs$$ and therefore $$\rho=\frac {W}{Vgs}$$

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