Tag Info

New answers tagged

1

My argument would be something along the following lines: assume that your spacetime is $\mathbb E^4$ and determine its isometry group. This turns out to be $O(4)\ltimes\mathbb R^4$, which doesn't coincide with the Galilei group (indeed in special relativity $O(1,3)\ltimes\mathbb R^4$ is the full Poincaré group, which is also the isometry group of flat ...



Top 50 recent answers are included