New answers tagged experimental-technique
2.6 million counts, with each count producing a dead time of 90 nsec, gives a total dead time of .234 seconds / second. So the total number of counts should be 3.4 million counts (2.6 / (1 - .234), assuming no dead time. Since each QD emits 770 million photons per second, the detector efficiency is 3.4 / 770 (which I get as .44%).
There is nothing like bubble chamber photos to clarify such issues. Here is an anti Lamda: The part relevant to your question is that we can measure with an accuracy of microns the vertex of the decaying antilamda, and with an accuracy of an MeV/c the momenta of the particles it decays into, an antiproton and a pion. The antiproton identifiable by ...
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