# Tag Info

## Hot answers tagged everyday-life

28

In general the answer is "yes it is possible" - but in your case the answer is "that is not a Faraday cage". Radio waves are (partially) reflected by any discontinuity in dielectric constant of the medium they propagate through. The ones that propagate (through walls etc) will also experience attenuation. A faraday cage is a continuous conducting structure ...

16

Just to add to what Floris has said. It is frequent (in the UK) that institutional settings would have toughened glass in windows, particularly in bathrooms, gyms etc. that would have the form of a wire mesh (of order 1cm grid) embedded in the glass. That would do a particularly good job of blocking phone signals that would otherwise penetrate the glass.

10

From Wikipedia: Paraffin wax is a white or colorless soft solid derivable from petroleum, coal or oil shale, that consists of a mixture of hydrocarbon molecules containing between twenty and forty carbon atoms. As stated above, paraffin wax is a hydrocarbon that is a soft solid at room temperature. When it melts, it becomes the combustible fuel for the ...

4

A crude model of the UTE is used simulate the pressure field created by the car as it travels through atmospheric air. We must determine the pressure in truck bed because it applies force on the surfboard. The car travels at a constant $60 ~\text{mph}$ (an arbitrary, worst-case value). UPPER: The velocity profile of air flowing around the car. ...

3

Sorry but surf boards do fly out. You may not have experienced it personally but keep doing it the way you are and you are bound to experience it. If you are thinking that as the velocity of the air travels over car it is some how holding the boards in you are incorrect. Check out this article http://www.gcdataconcepts.com/carairflow.html "Actually the ...

3

Let $m_1$ be the mass of the peas, which we'll assume to be mainly water, $m_2$ the mass of boiling water added and $m_p$ the mass of the pan. We'll assume no heat losses. After adding everything to the pan and allowing for thermal equilibrium to be established the temperature of pan, water and peas is $T$. $T$ can be calculated from the adiabatic heat ...

2

You have to lift up your body mass under the presence of gravity, so you have to overcome the force of gravity. While climbing up the stairs you have to put force on ground, more then your weight, which put same force but in opposite direction i.e. on you. Suppose your mass is $m$, then while climbing up, if you resolve the forces then, N-mg=ma\text{, } ...

1

When moving up you are pushing yourself in the opposite direction of the force of gravity. Therefore you do a positive work which is approximately $mgh$ ($h$ is the height of the step). While coming down gravity will do the same work for you.

1

It is more difficult because it requires more energy. Once you are up to speed, walking on a flat surface requires only enough energy to overcome friction, air resistance, and the energy to move your legs. Walking up stairs is more difficult because you additionally have to provide the energy to lift your body weight up the stairs. It's the difference ...

1

Basically the whole kinetic energy is transfered to pressure, and then this pressure will be transfered to kinetic energy again; this time only the direction is as defined by hydrostatic pressure; perpendicular to surface. This above gives a following basis; Kinetic energy of the ball is also it's potential energy (no friction on fall) Ekin = m g H This ...

1

I'm fairly certain that the energy difference between the two is negligible. Any heat as a result of light absorbed is localized on the roof, with layers of insulation between the inside of your house and the additional heat generated. Most of the additional energy absorbed would heat up the air rather than the inside of your house. Additionally, the optical ...

1

The color of an object says something about its emissivity/absorbance for visible radiation. But it has virtually no correlation to the behavior at IR wavelengths. A white object may reflect significantly more visible light than a black one, but may reflect identical amounts in IR. Since your roof will not be cooling via visible radiation, the color ...

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