# Tag Info

## Hot answers tagged electrostatics

5

The force on the conductor must be zero. We will solve the problem in two steps. First, we will write down the external force $d\mathbf{F}$ on each infinitessimal charge $dq$ in terms of the external field $\mathbf{E}_{ext}$ and then we will integrate $d\mathbf{F}$ to get the total force. Note we need only consider the external force (i.e., the force from ...

4

Yes, applying an electric field does create a pH gradient and in fact you can observe this simply by adding a suitable indicator to your system. For example see the section Demonstration of pH Gradient Formation in this article.

3

I don't think it is that tough to analyse. If a conductor is present in a uniform electric field then there will be redistribution of charges to counter Electric Field inside the conductor (so that the net field inside the conductor is zero). However in uniform electric field this redistribution of charges will not cause any net force on the conductor. Why? ...

2

Your calculation is nice, and the answer seems correct. Another way (less nice) to calculate it is to imagine the charge in the center as a small charged ball (to avoid infinities) and calculate by how much is the field energy lower when it is in the center than when it is far away. Due to symmetry and the Gauss law, the electric field in the former case is ...

1

If the wire is flexible, you could change its bounded area $A$, thus changing the magnetic flux. I'm imagining a "closed" loop where the two ends of the wire meet up. In your case of case of a uniform field that's perpendicular to plane of the wire, $\Phi_B=\pm BA$, depending on your choice for the direction of the corresponding area vector. Then, if you ...

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