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There have been lots of experimental attempts to test the validity of Coulomb's $r^{-2}$ law. Many of these are reviewed by Tu & Luo (2004), and is where I am getting the numbers quoted below. Somewhat equivalently, experiments have looked at trying to set an upper limit to the photon mass, which is testing the hypothesis that rather than a $r^{-1}$ ...

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Charge means that the body experiences a force in an electric field. A charge generates an electric field, which generates a force on other charges particles. Two bodies are said to repel if they force each other away and two bodies are said to attract if they force each other closer together. Now, I'm not really answering your question here of "why," I ...

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Coulombs law as well as Amperes law and similar mathematical formulations of two centuries ago, were incorporated within the strict mathematical format of Maxwell's equations . The apparently disparate laws and phenomena of electricity and magnetism were integrated by James Clerk Maxwell, who published an early form of the equations, which modify ...

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This the kind of question that can be solved by the method of images. Try placing a fictitious charge on the other side on the conducting plane. You should arrange it in such a way that the electrostatic potential is precisely zero on the surface of the conductor. If your case you put it at equal distance as the first but on the other side. The physical ...

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Note that $\mathbf r(t)$ is the trajectory (a priori unknown) of a charged particle in an external electric field. Now consider the ansatz $\mathbf r(t) = \mathbf r_0(t) - \mathbf a(t) \cos \Omega t$, which is motivated by the solution for a homogeneous electric field $\mathbf E(t) = \frac{m\Omega^2}{q} \mathbf a \cos \Omega t$. Here $\mathbf r_0(t)$ is a ...

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The first equation assumes the external electric field (caused by the charges on the plates of the capacitor) doesn't change. When a battery is connected, it can fill and discharge the plates as necessary to maintain the voltage. So, the E_0 value increases as you add the dielectric.

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According to Richard Feynman, the charge is the probability of a particle interacting by the electro magnetic force. More specifically it describes the amplitude of the "probability arrow" of a certain electromagnetic interaction taking place. Much like @Asher has mentioned already, the standard model cannot provide an explanation for why certain particles ...

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I might be erring something basic here, so downvotes are welcomed, but I would love if they include comments to correct this answer, or just erase it. I do not believe the Coulomb law has been tested beyond the order of a few meters. Arguing that light remains unchanged across the universe should be irrelevant. The reason is that the electrostatic and ...

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I asked a somewhat different, yet similar question.Hope this helps! Why is an $LC$ oscillator lossless, but $C V^2 / 2$ energy is lost to a capacitor connected to an ideal voltage source?

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First, the Wikipedia article already says on the derivation of Gauss' law from Coulomb's law: Note that since Coulomb's law only applies to stationary charges, there is no reason to expect Gauss's law to hold for moving charges based on this derivation alone. In fact, Gauss's law does hold for moving charges, and in this respect Gauss's law is more ...

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Remember Lenz's Law: as you change the flux through a coil, an e.m.f. is generated that opposes this change. Therefore, if I have two coils that are a certain distance apart, they will have a certain "shared" flux - flux due to $A$ appearing in coil $B$, for example. Now if we bring $A$ closer to $B$, we change the flux in $B$ due to $A$, and will get a ...

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