# Tag Info

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I like to think about potentials as a hilly landscape. A ball rolling in this landscape will have an energy relative to how high the hill is wherever the ball is at. If it is up higher on the hill, the ball will have less kinetic energy, and lower in the valley, the ball will have more kinetic energy. The amount of kinetic energy the ball has is related ...

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$E$ is necessarily zero inside hollow sphere because, Inside hollow sphere $Q = 0$ from gauss’s law $$\phi=\frac{Q}{\epsilon}$$ $$E.A = \frac{Q}{\epsilon}$$ Since, $E.A = 0$ $E = 0$ or $A = 0$ but $A\ne0$ so $E = 0$

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Okay, draw a circle around the spherical void; done? Then see is there any charge? If not, there should not be any divergence of electric field, know that? So, from Gauss Law, $$\text{div} \mathbf{E} \cdot dv= 0$$ which implies $$\mathbf{E}\cdot d\mathbf S= 0 \implies \mathbf E= 0$$ over that volume . Edit: Don't know what OP is trying to convey ...

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It depends exactly what you want this to do. The nearest thing might be a high frequency discharge from a Tesla Coil channeled through an Argon gas stream

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Electric fields are all around us. Any atom or molecule is made from protons and electrons (and neutrons too of course) with their positive and negative charges. In most the cases this electric charges are equally distributed in bodies, the bodies are electric neutral. If one uses a battery or an electric generator - they always have a source and a sink and ...

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It sounds like you want to project your electric field a significant distance from whatever is generating it, like a hose sprays water. Unfortunately, you can't. Like static magnetic fields, static electric fields don't have anything that behaves like momentum, so they take the least-energy path from the positive source charges to the negative source ...

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Yes surely, The pulsating DC is impure dc. Each pulse will be creating a change in magnetic flux in the transformer core. If you see the normal ac diagram the wave from 0 to T, It is similar to your pulsating DC diagram, there is a change in flux in transformer in this case. But it interesting to note that the transformer will give the increased or ...

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As long as the DC component does not saturate the core of the transformer, the (lower frequency) components of the waveform should be induced in the secondary. Consider, for example, the output transformer of a single ended class A triode audio amplifier Image credit In this case, the primary current is 'pulsating' DC, i.e., the primary current varies ...

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When you first connect the source, there is a very brief transient during which the steady-state DC solution is set up. The speed of the signal, i.e. the electromagnetic wave front that carries the information along the wire, is a bit less than the speed of light because of transmission line effects. Figuring out exactly how long the transient lasts would ...

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You appear to have some impression of the electric field which has given you the idea that it's some sort of bubble or something around an electron, for example. It's not. There's no real way to answer your question other than that that I can think of. It doesn't somehow fit itself through the slit or anything like that really.

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Electricity is neither positive or negative as that is just a phrase attempting to explain it and is wrong ! To fully understand electricity we need to view it as a vacuum where positive is a gain in pressure and negative as like an empty void with space between them ! Here we consider space as time and the rate of charge is time over space ! Volts is the ...

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In general, no: the field of a charge distribution $\rho$ is not the same as the field of a point charge at some point therein, except for some very particular cases (the one that everyone should know is that any spherical shell of charge has an inner field of 0 but an outer field that looks exactly like all the charge is located at the center point. A ...

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Let's think about the circuit you drew. It contains a battery, switch, bulb, and a very large inductor. In fact, the inductance of a wire that goes 10 times around the Earth can be calculated (I am going to assume an air core - in fact there is a piece of iron in the middle of the Earth which makes the resulting inductance greater). $$L\approx N^2 R \mu_0 ... -5 Electricity actually flows faster than the speed of light. If you think of electrons as each having a little engine, it makes it very easy to understand. I hope this helps. Edit: There seems to be some confusion as to my statement so I'm going to clarify. Okay. Then. Imagine I've got a block. I pull the block. It moves. Now, imagine I've got two blocks, ... 0 So, I think I got it thanks to the tips you two gave me. As you mentioned, my single electric fields weren't incorrect, but I have to put them into the same coordinate system. The electric field for the wire running along the x-axis should look something like this then: ... 0 If Instead of that positively charged cat we use an iron nail (which is also moving in sync with the current like that cat which was moving previously), You are asking what if you had a stationary neutral wire with a current and you moved a piece of iron so that it moved at the rate the mobile charges moved why would it react? If you go back to the ... 0 When dealing with infinitely long line charges (basically a cylindrical geometry) calculating the potential relative to infinity becomes a problem. You have to establish a reference (ground/earth) at a finite location. So, your result of an infinite potential difference is not incorrect, although it is confusing the first time you see it. This site ... 0 The explanation is simple. Start with a definition of voltage: the work done moving 1 coulomb of charge from point a to point b. In this case a to b is one plate of the capacitor to the other, since we are talking about the voltage across the capacitor. And now a definition of the work done: it's \text{force} \times \text{distance}. A capacitor ... 1 Capacitance is about stored charge - more electrons flowing into something than flow out. This can happen in a piece of wire, although it can take a large amount of applied voltage to accumulate a small amount of excess electrons. In other words, a simple piece of wire has very low capacitance. Even a straight piece of wire will have inductance because any ... 0 The reason I give is simply that attraction from some opposite charge induces motion in an electron. The resistance to its flow is caused by the medium. If the medium was empty, there would be no resistance, hence empty space should conduct electricity better than copper wires! A metal wire is conductive because metals have lots of energy levels near ... 0 If c is unknown, then you don't know it and you'll have to leave it (either directly or in another form, like \rho or Q) as a variable in your expressions. So indeed you can either replace c with \rho/r^2 or Q / (4\pi R^5/3), but you cannot eliminate it completely unless they ask for some problem with a very fortuitous cancellation. 0 Observables like quantised energy levels and quantised angular momentum of an atom are obtained by finding eigensolutions of the Schrödinger Equation (here for the Hydrogen atom). Separation into three parts allows to obtain the Colatitude and Azimuthal equations which allows to calculate the quantised angular momentum of the hydrogen atom, giving rise to ... 2 E_1 = E_2 . since E is independent of dielectric as long as potential b/w plates is constant.$$E= = -\frac{dV}{dr}$$So, it is independent of dielectric b/w it. So, correct statement would be$$E_1d = E_2dEd = Ed

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You seems to assume both capacitors has the same plate separation $d$. So, lets assume that. Assume there is no dielectric material. Therefore, nicely $Ed = Ed$ in both capacitors. Which is nice. :). Now, I think I understand your confusion. Have an isolated capacitor with electric field inside plates of $E$. Insert dielectric $K$. Under this case, the ...

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