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5

Voltage is similar to height. It plays the same role for electric charge as height*gravity does for a ball on a hill. So high voltage means high potential energy the same way a ball being high up on a hill means high potential energy. Voltage is not potential energy, the same way height is not energy. However, if you have a certain amount of charge $q$, you ...

3

When two resistors are in parallel, the voltage across them is the same, but the current through them might be different. The current through the parallel elements will add to form the total current, giving $I = \frac{V}{R_1} + \frac{V}{R_2}$. Manipulating this to get V/I in terms of R1 and R2 will get you the formula for parallel resistors, $R_{eq} = ... 2 The analogy is wrong. A voltage source can only shock us if it is able to pass a considerable amount of current through our body ( ~ 250 mA or so, I dont know the exact value but you can Google it ). The circuit that you are trying to discuss, does indeed have 36 Amps of current flowing through it, but once you connect yourself to the circuit, you are in ... 1 Resistances, in series, add: $$R_{EQ} = R_1 + R_2$$ This follows from KVL and Ohm's Law:$V = IR$. Since series connected circuit elements have identical current$I$through: $$V_{EQ} = IR_1 + IR_2 = I(R_1 + R_2) = IR_{EQ}$$ Conductances, in parallel, add: $$G_{EQ} = G_A + G_B$$ This follows from KCL and the dual of Ohm's Law:$I = VG$. Since ... 1 A few preliminary ideas which might help: It doesn't really matter what the speed of the electrons is - a current of 1 C/s (=1 A) just means that a coulomb worth of charge (equal to$6.2 \times 10^{18}$electrons) passes each point in the circuit each second. Perhaps there is one electron travelling so fast that it does$6.2 \times 10^{18}\$ laps of the ...

1

First a minor quibble. Reactance is the imaginary part of impedance and is thus real. $$Z = R + jX$$ Thus, inductive reactance is: $$X_L = \omega L$$ Second, reactance is the imaginary part of impedance. So, to fully understand why this is, you must understand the notion of impedance. For the ideal inductor, we have that the voltage across is ...

1

In the absence of supporting information, it's hard to say where to start. Do you have a circuit diagram, at least? Typically one would identify certain nodes at which the voltage(s) are known, then trace all electrical paths to figure out which capacitors have that node in common (suggesting parallelism), and which capacitors are connected in sequence on ...

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