# Tag Info

## New answers tagged distributions

3

Well, you know that the eigenfunction of $\hat p$ is $\exp(ipx)$, so let's try to find what the expectation value of $x$ is, to begin with: $$\langle p | x | p\rangle = \int \exp(-ipx) x \exp(ipx) \, dx = \int x\, dx$$ and this integral doesn't exist. Then it shouldn't come as a surprise that trying to take the time derivative gives nonsense. The underlying ...

0

Update: Comments by Robin pointed out my confusion. Consider the following: $$[x, p^2] = x p p - p p x = x p p - p x p + p x p - p p x = [x,p] p + p [x,p] = 2 i h p$$ If you plug this in the initial expression, you will get exactly what you would expect from this observable: $p/m$. But formally correct manipulations that you performed provide a ...

Top 50 recent answers are included