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Meter is a unit of distance, meaning that your extra dimension in which you want to measure has to be a dimension of space, also called a spatial dimension, if you want to use the unit meter. There also are dimension of time. These are called temporal dimensions. Since meter isn't a unit of time, you can't measure anything in such a dimension with meter as ...


I would say yes (although this is non-physical). Assuming that your extra dimensions are ones of distance, you're just adding another axis. Maybe of interest to you would be googling "metric spaces" which are somehow generalizations of distance.


I should trust my mathematics and give myself the benefit of the doubt in my physics recollection - indeed, after graphing it, intuition failed me, and the slow-down required is very minor:


The answer by ryanp16 gives a great derivation of the equation you're asking about using calculus, and in fact, that is the approach that I would have taken had I not seen his answer. However, if you're not familiar with calculus, there's a second, algebraic approach that you can use to arrive at the same conclusion. I like to take this approach with high ...


Acceleration $a$ is defined as the rate of change of velocity $v$ with respect to time $t$, or $a=\frac{dv}{dt}$. For constant acceleration we can integrate both sides with respect to $t$ to obtain $v=u+at$ where $u$ is the velocity at our initial time $t=0$. Since velocity $v$ is defined as the rate of change of displacement $s$ with respect to time we ...

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